Calculating sand penetration of ice solid from height X

AI Thread Summary
The discussion revolves around calculating the drop height required for a 30cm timber stick encased in ice to penetrate sand, leaving 40cm exposed above the surface. Factors influencing this calculation include the density and composition of the sand, the dimensions and mass of the ice, and gravitational acceleration. There are references to "young penetration equations" that could assist in determining the necessary drop height, although achieving a 60cm burial depth with the described ice shape poses challenges. The conversation also hints at potential rigging in the bet, questioning the length of the stick. Overall, the feasibility of the scenario depends on various physical parameters and precise calculations.
MattRNR2
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G’day physics forum

This is a purely hypothetical question and my knowledge of physics is rather limited so I’ve no idea if answering it is even possible however here goes:

Imagine a 30cm long timber stick approximately 3mm in diameter that has been placed vertically in an inverted pyramid or conical mold (approximately the size of a ice-cream cone) filled with water and frozen so when removed it is frozen in the middle of a solid block of ice that tapers to a point.

I’m trying to work out at what altitude this object would need to be dropped in order to impact a surface composed of a certain substrate (say sand) and penetrate such that n cm (say 40cm) of the timber post would be exposed above the surface and the block of ice and ‘1m – n cm’ (i.e. 60cm) were buried beneath the surface.

I’m guessing such an equation would require a measure of the substrate density, weight and dimension of the ice and gravitational acceleration.

If anyone out there has any idea how this can be achieved or at the very least whether or not this can be achieved give us a yell.

Regards

MattRNR2

Incidentally there is a beer riding on this so suffice to say I'm taking it pretty seriously
 
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MattRNR2 said:
30cm long timber stick
MattRNR2 said:
(say 40cm) of the timber post would be exposed above
MattRNR2 said:
and ‘1m – n cm’ (i.e. 60cm) were buried beneath the surface.
MattRNR2 said:
can be achieved
"Achieved?" Yes, ... BUT ...
Most "bar bets" are rigged. The rigging on this bet may be as simple as stretching the 30 cm stick to 1 meter. If that's just a transcription artifact, sure, there are ways to work out drop heights for what you've described.
 
It will depend on the sand (composition, amount of water, ...), the angle of the ice, the mass of the ice and many other factors.

60 cm sounds very problematic with an ice-cream-cone-shaped object.
 
Google "young penetration equations" for a Sandia report. Assuming that the ice remains intact, they should work.
 
MattRNR2 said:
Imagine a 30cm long timber stick approximately 3mm in diameter that has been placed vertically in an inverted pyramid or conical mold (approximately the size of a ice-cream cone) filled with water and frozen so when removed it is frozen in the middle of a solid block of ice that tapers to a point.

I’m trying to work out at what altitude this object would need to be dropped in order to impact a surface composed of a certain substrate (say sand) and penetrate such that n cm (say 40cm) of the timber post would be exposed above the surface and the block of ice and ‘1m – n cm’ (i.e. 60cm) were buried beneath the surface.
and your 30cm stick suddenly became 100cm ( 1m) long ??
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
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