MHB Calculating Sand Volume for a Cylindrical Containment Vessel

Click For Summary
To calculate the sand volume required for a cylindrical containment vessel enclosing a spherical pressure vessel, first determine the volume of the cylinder and the sphere. The sphere has a diameter of 10 m, leading to a radius of 5 m, while the cylinder's dimensions must be established based on the sphere's size. The correct approach is to subtract the volume of the sphere from the volume of the cylinder to find the volume of sand needed. This calculation ensures that all space in the cylinder is filled with sand, providing the necessary support for the sphere. Accurate volume calculations are essential for effective containment and safety.
nathan12345
Messages
1
Reaction score
0
A spherical pressure vessel with a diamter of 10 m is tightly enclosed in a cylindrical containment vessel with the sphere just touching on all 4 sides . Additional protective material (assume is sand ) is added to the cyclinder to provide additional support .How much sand is required so that all the space in the cylinder is filled ?
I am beginning a new course , and I am pretty new to the topic , but in my head I would calculate the volume of the sphere , and then the cylinder , and subtract the volume of the cylinder from the volume of the sphere ? .
 
Mathematics news on Phys.org
Right... but it's the other way around: subtract the volume of the cylinder from the volume of the sphere...
 
subtract the volume of the sphere from the volume of the cylinder

BA9B4A01-2E3A-40AB-A27A-1E9683FCC772.png
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...