Calculating Satellite Height and Velocity for Geostationary Orbit

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To calculate the height and velocity of a satellite in geostationary orbit, it must match the Earth's angular velocity to remain over the same geographical point. The relevant equation for velocity is v = sqrt(G*m / r), where r is the distance from the center of the Earth. The satellite's velocity will differ from the Earth's due to the different radius of orbit. Understanding angular velocity is crucial, even if it hasn't been explicitly covered in the coursework. This relationship is essential for determining the satellite's required parameters for a stable geostationary position.
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Homework Statement


Calculate at what height above the Earth's surface a satellite must be placed if it is to remain over the same geographical point on the equator of the earth. What is the velocity of such a satellite?

Homework Equations


v = sqrt(G*m / r)

The Attempt at a Solution


At first I thought the velocity of the satellite would have to be the same as the earth, but since r is different the velocity must also be different. I have 2 unknowns for the satellite, the velocity and r, and can't figure out what to do now.

Thanks for your help.
 
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Gauss177 said:
At first I thought the velocity of the satellite would have to be the same as the earth,
It must have the same angular velocity as the earth.
 
Hm..we haven't covered angular velocity yet. Is there another way to do it?
 
Whether you've explicitly covered angular velocity or not, there's no way around the fact that if the satellite is to "remain over the same geographical point" its angular speed must equal that of the earth. If you think in terms of both the Earth's surface and the satellite sweeping out equal angles in equal times, that might help you figure it out.
 
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