Calculating Speed of Meterstick Swinging Vertical - Physics

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The discussion focuses on calculating the linear speed of the end of a meter stick swinging vertically after being released from a horizontal position. The calculated speed for part C is 5.42 m/s. The user initially struggles with part D, which involves finding the ratio of this speed to the speed of a particle that has fallen 1.00 m from rest. Clarification is sought on how to approach part D, leading to a realization that the problem requires a ratio rather than a direct calculation. The conversation highlights the importance of carefully reading the problem statement to avoid confusion.
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A stick with a mass of 0.152 kg and a length of 1.00 m is pivoted about one end so it can rotate without friction about a horizontal axis. The meter stick is held in a horizontal position and released.
C-As it swings through the vertical, calculate the linear speed of the end of the stick opposite the axis.
D-Find the ratio of the speed of a particle that has fallen a distance of 1.00 m, starting from rest, to the speed from part (C).
For part C I got 5.42 m/s I just cannot figure out part d. Any help would be greatly appreciated!
 
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lina29 said:
A stick with a mass of 0.152 kg and a length of 1.00 m is pivoted about one end so it can rotate without friction about a horizontal axis. The meter stick is held in a horizontal position and released.
C-As it swings through the vertical, calculate the linear speed of the end of the stick opposite the axis.
D-Find the ratio of the speed of a particle that has fallen a distance of 1.00 m, starting from rest, to the speed from part (C).
For part C I got 5.42 m/s I just cannot figure out part d. Any help would be greatly appreciated!

Welcome to the PF.

Please show us your work for how you got part (C).
 
v=rw= (1 m)(5.42 rad/s)=5.42 m/s
 
Never mind I didn't read the problem correct. I didn't realize it said ratio :)
Thanks anyway!
 
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