Calculating String Tension for Hanging Picture (50N)

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To calculate the tension in a string hanging a 50N picture at a 40-degree angle, it's essential to apply Newton's Laws and draw a free body diagram to visualize the forces. The picture is stationary, indicating that the sum of forces equals zero, which means the tension must counteract the weight of the picture. The discussion emphasizes the importance of resolving the tension vector into its components based on the angle. There is some disagreement about the notation used for vectors, with suggestions to simplify the explanation for beginners. Understanding that tension is the force exerted by the string to balance the weight is crucial for solving the problem effectively.
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I need to work out the tension in a piece of string when hanging a picture off one nail on the wall. All I know is that the weight of the picture is 50N and the angle of the sides of the string are at a 40 degree angle from the top of the picture. I have no idea of even how to start working this out. Can anyone help?
 
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I would begin by drawing a free body diagram labelling all the forces and their orientations.
 
Energize said:
I need to work out the tension in a piece of string when hanging a picture off one nail on the wall. All I know is that the weight of the picture is 50N and the angle of the sides of the string are at a 40 degree angle from the top of the picture. I have no idea of even how to start working this out. Can anyone help?

Draw a force diagram
Apply Newton's Laws

Realize that the picture is not moving, thus it's velocity is zero. Newton's law will drop down to:

\sum \vec F_i = 0

Remember that you can write a vector as:
\vec T = \hat T |\vec T|

or in a more familiar notation,
\vec T = \hat i \, T \cos \theta + \hat j \, T \sin \theta

does that help?

hint: you will need to solve for T
 
Are you familiar with free body diagrams, which show all the forces on objects? Does you textbook have a similar examples worked out for you where there are cables or strings involved?

EDIT -- Oops, I was too slow!
 
Um, I disagree with this:

\vec T = \hat i \, T \cos \theta + \hat j \, T \sin \theta

This is bad practice and should be avoided.
 
The only force acting on it is gravity, our class hasn't drawn any of these diagrams you speak of or seen that formulae before, I've just started AS and our teacher just gave us this sheet with loads of questions on without even teaching us about tension yet.

/\
/ \
/ \
/40o 40o\
------------
| |
| |
--------------
50 Newtons
 
Last edited:
Energize said:
The only force acting on it is gravity, our class hasn't drawn any of these diagrams you speak of or seen that formulae before, I've just started AS and our teacher just gave us this sheet with loads of questions on without even teaching us about tension yet.
See if this info from wikipedia helps:

http://en.wikipedia.org/wiki/Free_body_diagram
 
cyrusabdollahi said:
Um, I disagree with this:

\vec T = \hat i \, T \cos \theta + \hat j \, T \sin \theta

This is bad practice and should be avoided.

Yeah, I posted that rather quickly. I disagree with it too.

I should have just said something along the lines of resolving the vector into its components via the angle between them. Because what I wrote only holds for a subset of problems.

Do you think I should edit it out?

On a side note, I personally hate the \hat i, \,\, \hat j \,\, \hat k notation.
 
Energize said:
The only force acting on it is gravity, our class hasn't drawn any of these diagrams you speak of or seen that formulae before, I've just started AS and our teacher just gave us this sheet with loads of questions on without even teaching us about tension yet.

/\
/ \
/ \
/40o 40o\
------------
| |
| |
--------------
50 Newtons

If the only force acting on it was gravity it would continue to fall forever in the direction of the gravity vector.

Imagine a balloon hovering in the air. What forces act on it?
Well of course gravity does.
Then the helium in the baloon is trying to rise which creates an upwards force right?

Well since the balloon is hovering (ie not moving) the "helium" upward force, and the gravity downward force must be equal. You can think of that "helium" force as the force applied to the string. That force is the tension.

Does that makes sense?
 
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FrogPad said:
Yeah, I posted that rather quickly. I disagree with it too.

I should have just said something along the lines of resolving the vector into its components via the angle between them. Because what I wrote only holds for a subset of problems.

Do you think I should edit it out?

On a side note, I personally hate the \hat i, \,\, \hat j \,\, \hat k notation.

Nah, so long as he knows its not a 'formula'
 
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