Calculating Tangential Velocity: 0.45kg Ball, 45N Force

AI Thread Summary
To calculate the tangential velocity of a 0.45kg ball subjected to a 45N force in circular motion, the centripetal acceleration must first be determined. The centripetal force formula, F = m * a, can be rearranged to find acceleration, where a = F/m. The relationship v = r * ω can be utilized, with ω derived from the centripetal force equation F = m * r * ω². By substituting the known values into these equations, the tangential velocity can be calculated. Understanding these relationships is crucial for solving the problem accurately.
sw3etazngyrl
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Suppose a 0.45kg ball is attached to a 1.00m long string. the force keeping the ball oving in a circular path is 45 N. What will the ball's centripetal acceleration and tangential velocity be?



I got the first part, but I'm not sure how to get the 2nd part.



So, I'm using v=r*omega. To find omega, I want to use F=mr*omega^2. Will that work?
 
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Will you show the calculations in numbers?
 
sw3etazngyrl said:
So, I'm using v=r*omega. To find omega, I want to use F=mr*omega^2. Will that work?
Probably. BTW, the bold face is hard to read.
 
The force keeping the ball in circular path is the centripetal force. Since f=ma, and we know that "a" must be the centripetal acceleration. What is centripetal acceleration equal to (you already found this, from there you should realize the a_cent is also equal to something else).
 
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