Calculating Telescope Length: Refracting Telescopes

AI Thread Summary
To achieve an image 40 times bigger in a refracting telescope with a lens diameter of 1.02 m and a focal length of 19.4 m, the telescope's length must be calculated based on the magnification formula, which relates the focal lengths of the objective and eyepiece lenses. The required length of the telescope will be determined by the focal length of the eyepiece lens needed to achieve this magnification. Additionally, understanding the relationship between the focal lengths and the telescope's overall design is crucial for optimal performance. For further insights into elementary optics, resources that explain these principles in detail can be beneficial. The calculations and principles discussed are essential for anyone interested in telescope design and functionality.
edoarad
Messages
19
Reaction score
0
in a refracting telescope, the lens's diameter is 1.02 m and its focal length is 19.4 m.
how long must the telescope be to get an image, 40 times bigger?

i would also like to get a link to a site explaining this kind of elementary optics.
 
Physics news on Phys.org
just saw the warning, please don't delete my posts :S they are in a close enough format i think..
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

How Do You Calculate the Focal Length of a Telescope's Objective?
Replies
2
Views
2K
Calculating focal length from a number of focal ratios
Replies
5
Views
3K
Calculate a radius of a circle on a screen
Replies
3
Views
1K
Reflecting telescope optics problem-Angle on the sky to angle on a mirror
Replies
1
Views
5K
I Condition for Centering Starlight in a Water-Filled Telescope?
Replies
6
Views
2K
Stargazing Calculating the Resolving power of a Telescope
Replies
7
Views
4K
Astronomy Technical, physical text on (astro)photography & telescopes?
Replies
2
Views
1K
How Does the Galileoscope's Optical Design Affect Its Viewing Capabilities?
Replies
1
Views
2K
I Phase Contrast Telescope - Part II
Replies
25
Views
2K
Height of the image of Jupiter created by the objective lens
Replies
3
Views
1K

Hot Threads

Recent Insights

Back
Top