Calculating Temperature of Liquid with Electrical Energy

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Discussion Overview

The discussion revolves around calculating the temperature of a liquid based on the resistance change of a platinum wire used for heating. The focus includes theoretical aspects of resistivity and temperature dependence, as well as practical algebraic manipulation of the relevant equations.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant presents a problem involving the resistance of a platinum wire at two different temperatures and seeks assistance in determining the liquid's temperature.
  • Another participant suggests researching the resistivity of platinum as a function of temperature, indicating that external resources may be helpful.
  • A participant proposes a formula relating resistance and temperature, attempting to set up the equation to solve for the unknown temperature.
  • Another participant raises a question about the temperature scale being used (Celsius or Kelvin) and inquires whether the difficulty lies in algebra or another aspect of the equation.

Areas of Agreement / Disagreement

Participants have not reached a consensus, as there are different approaches to solving the problem and some uncertainty regarding the temperature scale and the specific difficulties encountered.

Contextual Notes

There is a lack of clarity on the assumptions regarding temperature scales and the specific algebraic steps needed to isolate the variable in the equation.

noypihenyo
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A platinum wire having a resistance 4.85 ohms at 20degree C
is used to heat a liquid. the resistance of wire 5.97ohms after a cetain time. Determine the temperature of the liquid.


please help me to answer this.
 
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Looks like you need to find out the resistivity of platinum versus temperature. What does a google search tell you? What are likely websites that you could go to to find that info? Or if you're old like me, what reference book would you pull down off the bookshelf to look it up?
 
this is the formula


R2 = R1 [ 1 + a(▲ t)] = 5.97ohms

the equation look loke this?

R2 = 4.85 [ 1 + .0038(20-x)] = 5.97ohms

i have some difficulties to find the value of x
 
First, double-check whether the temperature is supposed to be in C or K (absolute temp). Second, are you saying that you are having trouble with the algebra, or some other part of the equation?
 

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