Calculating the Commutator of x and p - Problem Discussion

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i have met a problem about the commutator of x and p.
[x,p]=ihbar

/p> is the eigenstate of momentum operator p.

<p/xp-px/p>

=<p/xp/p>-<p/px/p>

=p<p/x/p>-p<p/x/p> the second term is got by the momentum operator p acting on
the left state.

=0

so i get zero! is there anyone can point out where i am wrong?
 
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Can you calculate <p|x|p>? Which number will you get? I can tell you: any number you want, depending on how you decide to calculate it. You are playing pseudo-math with formal expressions without really understanding their mathematical meaning. That is how many paradoxes appear.

Many theorems in mathematics are valid under certain assumptions. Skip the assumptions, apply the theorem, and you can well create a paradox.
 
lihurricane said:
[...]
so i get zero! is there anyone can point out where i am wrong?

Take a look at Post #18 in this (very recent) thread:

https://www.physicsforums.com/showthread.php?t=426509&page=2

More importantly, check out the references I mentioned. :-)
 
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If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
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