Calculating the Force of Static Friction on a 2000kg Car

[yankees26an]

Homework Statement

A 2000kg car makes a left run of radius 6.5 m. If this turn is made in 2 seconds, what isthe force of static friction of the car during the turn?

Homework Equations

a = v^2/r, F = (m*v^2)/r ; d = v*t;

The Attempt at a Solution

d/t = v = 3.25 m/s

Fc = (m*v^2)/r = 3250

Fs(static friction) <= Fc

 

[Doc Al]

d/t = v = 3.25 m/s

What distance is traveled in making the turn? How would you calculate it?

 

[yankees26an]

Oh whoops the distance would be 2*pi*r/4 since it goes a quarter of a circle.

That would make d/t = 5.1 m/s

Fc = 3.2 kN. Still stuck from there

 

[Doc Al]

Oh whoops the distance would be 2*pi*r/4 since it goes a quarter of a circle.

That would make d/t = 5.1 m/s

Good.

Fc = 3.2 kN.

Don't forget to recalculate Fc using the corrected speed.

 

[yankees26an]

Good.

Don't forget to recalculate Fc using the corrected speed.

Yea I did but I forgot to square! Got it now thanks