Calculating the Gravitational Potential of a Spehrical Shell

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SUMMARY

The discussion centers on calculating the gravitational potential of a hollow spherical shell as described in Chapter 13-4 of The Feynman Lectures on Physics. The participants clarify that the mass of a ring-shaped slice of the sphere is denoted as dm, with the radius of the sphere represented by 'a' and the density by 'mu'. The term 'y' refers to the perpendicular distance from the center to the ring, and the relationship dx = ds sin(θ) is established to explain the thickness of the ring along the x-axis. The diagram accompanying the equations is essential for understanding the mathematical derivation.

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  • Understanding of gravitational potential energy
  • Familiarity with spherical coordinates
  • Basic knowledge of calculus, particularly integration
  • Concept of density in physics
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  • Study the derivation of gravitational potential energy for different mass distributions
  • Learn about spherical coordinates and their applications in physics
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  • Review calculus techniques for integrating over spherical shells
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Students of physics, particularly those studying classical mechanics, educators seeking to clarify concepts in gravitational theory, and anyone interested in the mathematical foundations of gravitational potential energy.

amolv06
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I'm going through The Feynman Lectures On Physics. I've taken a few classical physics classes before, however Feynman's detailed explanations are much better than anything I've gotten from my teachers. However, I'm having a little difficulty following the mathematics when he tries to show that a hollow spherical shell acts as though it has all its mass located at the center.

I will read the paragraph previous to the math I am having difficulty with, and then read off the math.

"We now demonstrate the correctness of this miracle. In order to do so, however, we shall consider a thin uniform shell instead of the whole earth. Let the total mass of the shell be m, and let us calculate the potential energy of a particle of mass m' a distance R away from the sphere and show that the potential energy is the same as it would be if the mass m were at the center. If we call x the distance of a certain plane section from the center, then all the mass that is in a slice dx is at the same idstance r from P, and the potential due to the ring is -Gm'dm/r. How much mass is in the small slice dx? An amount

dm=2*pi*y*mu*ds=\frac{2*pi*y*mu*dx}{sin(\vartheta)}=\frac{2*pi*y*mu*dx*a}{y}=2*pi*a*mu*dx

Here, a is the radius I believe. I don't know where he pulled y from. Mu is the density of a piece of the spherical shell.

What I can't understand is how he is doing the math for all this. Where does the sin theta come from? I'm slightly lost here.

This is in the Feynman Lectures, by the way.
 
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Can you tell me the chapter it's in, I have to see it in the book. I'll try to see if I can figure it out.
 
It's in chapter 13-4. Thanks.
 
amolv06 said:
Here, a is the radius I believe. I don't know where he pulled y from. Mu is the density of a piece of the spherical shell.

What I can't understand is how he is doing the math for all this. Where does the sin theta come from? I'm slightly lost here.
To understand what he's doing, refer to the diagram next to the equations. The diagram shows the meaning of x and y.

dm refers to the mass of the ring-shaped slice of the sphere. Yes, a is the radius of the sphere. y is the perpendicular (vertical) distance of the ring from the line O-P. Since ds is the length of the side of the ring, the thickness of the ring along the x-axis (which is the line O-P) is dx = ds \sin\theta.
This is in the Feynman Lectures, by the way.
Book I, chapter/page 13-9.
 
Ahh. That makes perfect sense now. Thanks a lot.
 

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