Calculating the Height of a Building Using Free Fall Time

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A stone dropped from a building takes 2.9 seconds to hit the ground, and the height of the building is calculated using the formula y = 1/2at^2, where a is the acceleration due to gravity (9.8 m/s^2). By substituting the values, the height is determined to be 41.2 meters. The assumption that the stone is dropped from rest is confirmed as a reasonable interpretation of the problem. The calculations and assumptions are validated by participants in the discussion. The final answer of 41.2 meters is accepted as correct.
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Homework Statement


A stone dropped from the top of a building hits the ground in 2.9 s. How high is the building?

a=9.8 m/s^2
yinitial=0
vinital=0
y=?

Homework Equations


y=1/2at^2



The Attempt at a Solution


y=1/2at^2

Plugging in what I know:
y=1/2(9.8m/s^2)(2.9s)^2
Simplifying:y=1/2(82.4) m
Answer: y=41.2 m

Is this correct? Thanks in advance for confirming! :-)
 
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Looks correct to me. That is, assuming it is dropped from rest. It doesn't explicitly say, but I think it this case it is a safe assumption.
 
Thank you! I believe it is, my physics teacher usually assumes so.
 
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