Calculating the Height of a Cliff Using Rocks

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To calculate the height of the cliff, the problem involves two scenarios: a rock dropped from rest and a rock thrown upward. The first rock takes 13 seconds to hit the ground, while the second rock, thrown upward, reaches a height of 3 meters and takes a total of 13.5 seconds to fall back down. The equations of motion can be applied to both scenarios to establish relationships between height, time, and acceleration due to gravity. By solving these equations simultaneously, the height of the cliff can be determined. This problem illustrates the application of kinematic equations in a scenario with unknown variables.
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This problem doesn't have a diagram or a picture so:


Suppose you land your spacecraft on a distant planet and disembark extremely close to the top-edge of a cliff. The planet's acceleration due to gravity is unknown and you want to know the height of the cliff. Utilizing your accurate watch you let a rock fall from rest off the cliff edge and note it takes 13.00 seconds to impact the ground below. Next, you throw up a second rock (from the cliff's edge) and it rises to a height of 3.000 meters. The total time (from release to impact) for the second rock to reach the ground is 13.50 seconds. Calculate the height of the cliff.


Thanks for any help!
 
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If it doesn't have a diagram or picture, then make a diagram or picture. You know your initial velocity, and the time it takes to fall to the bottom of the cliff in the first scenario. You don't know height or acceleration.

In the second scenario, you know that at the top of the upward throw, the velocity is going to be 0, and it takes 13.50 seconds to fall 3 + h metres. Again, you don't know the height or the acceleration.

Two equations, two unknowns.
 
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