Calculating the Mass of a Cycloid Wire with Constant Density | Integration Help

  • Thread starter Thread starter kasse
  • Start date Start date
  • Tags Tags
    Mass Wire
Click For Summary
The discussion focuses on calculating the mass of a cycloid wire defined by the parametric equations x=t-sint and y=1-cost, with a constant density D=k. The user attempts to compute the mass by integrating D*ds and finds ds=sqrt(2-2cost) but struggles with the integration of k*sqrt(2-2cost). They mention a useful transformation involving the half-angle formula, suggesting that sqrt(1-cos(t)) can be expressed in terms of sin(t/2). The conversation also touches on finding the centroid by integrating x*k*ds and the subsequent steps involving integration by parts. The overall goal is to derive the mass and centroid accurately through integration techniques.
kasse
Messages
383
Reaction score
1

Homework Statement



What is the mass of a wire shaped like the arch x=t-sint, y=1-cost (t from 0 to 2*pi) of a cycloid C that has constant density D=k?

The Attempt at a Solution



I must integrate D*ds. I find that ds=sqrt(2-2cost)dt. Is this wrong? If it's right, I don't know how to integrate k*sqrt(2-2cost).
 
Last edited:
Physics news on Phys.org
There is a trick. sqrt(1-cos(t)) can be written neatly in terms of sin(t/2). Check out half angle formulas.
 
m=8k is my answer then.
 
Last edited:
Dick said:
There is a trick. sqrt(1-cos(t)) can be written neatly in terms of sin(t/2). Check out half angle formulas.

I think it's supposed to be sqrt((1-cos(t))/2) that can be written in terms of sin(t/2), right?
 
Right. I didn't mean that they were equal - just that they were closely related.
 
Then I'll try to find the centroid, first the x:

Then I must integrate x*k*ds and multiply with 1/m=1/8k.

If I've done right, I'll have to integrate (t-sin(t)*sin(t/2). Is it time for another trick?
 
Not as tricky as the first one. t*sin(t/2) is a routine integration by parts. I would write sin(t)*sin(t/2) as 2*sin(t/2)*cos(t/2)*sin(t/2) using double angle formula and do a substitution. Nothing unusual here.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
20
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K