Calculating the maximum force of object 1 without prefix

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The discussion revolves around calculating the maximum downward force of object 1 in a physics problem involving moments and pivots. The left and right pivots can each support a maximum of 10,000 N upwards, while the second object exerts a downward force of 9,000 N. The initial assumption was that the maximum force of object 1 could be 11,000 N, but further calculations suggested it might be 9,000 N with an unknown distance 'y'. Participants are encouraged to clarify their calculations and the axis used for determining moments to resolve the confusion. Understanding the relationship between the forces and distances is crucial for finding the correct maximum force of object 1.
Marcos Leo
Hi,

I am busy now for a couple of days with a physics problem. I am not really into physics, so I hope you can help me out. Its about the maximum force of an object (object 1 in this case). I included an illustration.


Homework Statement



* The left and right pivot have an max of ten thousand N (upwards);
* The force of the second object is nine thousand N (downwards);
* The force of the first object is unknown (downwards)

Furthermore:

* Distances in meters are given, but ‘y’ is unknown;
* Also the first object has an fixed position, while the second can be moved, but has to be rightsided and within 20m of object one.

I am looking for the maximum force x in N of object 1.
Force_on_Object.png



The Attempt at a Solution



I studied some basics physics about ‘moments’ and know that clockwise = anticlockwise. From that perspective I first thought that maybe the simple solution was that the max of x is the maximum of the left and right pivot – the force of object 2, so 11 thousand N.

But that’s maybe too simple. So, I did some additional calculations, where I included the widths and distances into the calculations, and my final answer was that x=9000 and y=2. But, the more I think about this, how more I become confused.

Could someone help me out on this ‘puzzle’ and explain what the maximum of x is, and more importantly, why?
 
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Marcos Leo said:
Hi,

I am busy now for a couple of days with a physics problem. I am not really into physics, so I hope you can help me out. Its about the maximum force of an object (object 1 in this case). I included an illustration.


Homework Statement



* The left and right pivot have an max of ten thousand N (upwards);
* The force of the second object is nine thousand N (downwards);
* The force of the first object is unknown (downwards)

Furthermore:

* Distances in meters are given, but ‘y’ is unknown;
* Also the first object has an fixed position, while the second can be moved, but has to be rightsided and within 20m of object one.

I am looking for the maximum force x in N of object 1.
View attachment 211482


The Attempt at a Solution



I studied some basics physics about ‘moments’ and know that clockwise = anticlockwise. From that perspective I first thought that maybe the simple solution was that the max of x is the maximum of the left and right pivot – the force of object 2, so 11 thousand N.

But that’s maybe too simple. So, I did some additional calculations, where I included the widths and distances into the calculations, and my final answer was that x=9000 and y=2. But, the more I think about this, how more I become confused.

Could someone help me out on this ‘puzzle’ and explain what the maximum of x is, and more importantly, why?
please show the details of your attempt using the distances.
Which point did you take as your axis? What moment did you calculate for each force about that axis?
 
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