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eclecticmanic

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Tides are created by the gravitational attraction of the sun and moon on Earth. Calculate the net force pulling on Earth during a)New Moon b)Full Moon c)First Quarter Moon.

Mass of the Moon: 7.35 x 10^22 kg

Mass of the Earth: 5.98 x 10^24 kg

Mass of the Sun: 1.99 x 10^30 kg

Distance from the Earth to the Moon: 3.84 x 10^8 m

Distance from the Earth to the Sun: 1.50 x 10^11 m

Universal Gravitational Constant (G): 6.67 x 10^-11

F=Gmm/d²I solved for the force of Sun on Earth

F=(6.67 x 10^-11)(1.99 x 10^30)(5.98 x 10^24)/1.5 x 10^11 = 5.29 x 10^33

And Moon on the Earth

F=(6.67 x 10^-11)(7.35 x 10^22)(5.98 x 10^24)/3.84 x 10^8 = 7.63 x 10^28

I don't know where to go from there, I think finding the solution has to do with where the moon is facing and maybe it's the difference from the distance of the sun? help me please

Mass of the Moon: 7.35 x 10^22 kg

Mass of the Earth: 5.98 x 10^24 kg

Mass of the Sun: 1.99 x 10^30 kg

Distance from the Earth to the Moon: 3.84 x 10^8 m

Distance from the Earth to the Sun: 1.50 x 10^11 m

Universal Gravitational Constant (G): 6.67 x 10^-11

F=Gmm/d²I solved for the force of Sun on Earth

F=(6.67 x 10^-11)(1.99 x 10^30)(5.98 x 10^24)/1.5 x 10^11 = 5.29 x 10^33

And Moon on the Earth

F=(6.67 x 10^-11)(7.35 x 10^22)(5.98 x 10^24)/3.84 x 10^8 = 7.63 x 10^28

I don't know where to go from there, I think finding the solution has to do with where the moon is facing and maybe it's the difference from the distance of the sun? help me please

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