Calculating the number of steps in an escalator

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The discussion revolves around calculating the number of steps on a stationary escalator based on the movements of two individuals, A and B. A takes 50 steps while B takes 75 steps, with their step times having a specific ratio. The equations derived from their movements are x + y = 50 and 3x + y = 75, where x represents steps taken by A and y represents the escalator's movement. Solving these equations leads to the conclusion that the escalator has 37.5 steps when stationary. The calculations emphasize the relationship between individual step counts and the escalator's contribution to total movement.
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There is a escalator and 12 persons move down it. A takes 50 steps and B takes 75 steps while the escalator is moving down.Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps. Find the no.of steps in the escalator while it is stationary
 
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I think I am correct. Let x be the number of steps covered by A in the given time and let y be the steps escalator sailed. then
x + y = 50
3x + y = 75.
Thus we will get the answer y as to be 37.5
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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