Calculating the power transformed in a real battery

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The discussion centers on calculating the power transformed in a battery with an emf V, current I, and internal resistance R. The initial attempt suggests that the total power transformed is the sum of the power produced by the battery (P = VI) and the power dissipated due to internal resistance (P = I²R). However, clarification is needed regarding the relationship between these powers, as the electrical power produced by the cell is equal to the input power to the internal resistance. The conversation emphasizes understanding how these components interact rather than simply summing their values. Ultimately, the focus is on accurately defining the power dynamics within the battery system.
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Homework Statement


There is a battery producing emf V and the current around the circuit is I. The battery has an internal resistance of R. What is the power transformed by the battery

Homework Equations


P = VI
P= I2R

The Attempt at a Solution


Maybe P=VI+I2R because there is some electrical energy converted in the cell resulting in the power VI And then the same power is used to create power I2R in the internal resistance.
So shouldn't it be the sum of the two powers because it is the total power transformed.
 
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Faiq said:
Maybe P=VI+I2R because there is some electrical energy converted in the cell resulting in the power VI And then the same power is used to create power I2R in the internal resistance.

I think you are on the right lines but your explanation isn't very clear.

What do you mean by "then the same power is used" ?
 
Electrical power produced by cell = Input power to internal resitance
 
OK.
 
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