Calculating the Probability of Drawing All Diamonds from a Deck of Cards

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The probability of drawing three diamonds from a standard deck of 52 cards is calculated using the formula 13/52 * 12/51 * 11/50, which accounts for the decreasing number of diamonds and total cards after each draw. The initial confusion arose from incorrectly using 4/52, which refers to aces instead of diamonds. The correct probability is approximately 0.00144, significantly higher than the initial estimate of 0.000181. Additionally, the thread briefly touches on the ability to delete posts, indicating that only moderators can perform that action. Understanding the correct approach to calculating probabilities is essential for solving similar problems.
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Three cards are dealt from a standard deck of 52 cards. What is the probability that all of them will be diamonds?

If it helps, the topics for this unit are Bayes' Law, Problems involving permutations and combinations, problems involving Binomial Distribution, dependent events, independent events, and conditional probability.

What I've tried is 4/52 * 3/51 * 2/50 and the answer I've been getting (not necessarily correct, heh) is
(rounded) 0.000181 which seems way too small.

Unfortunately I don't know the correct answer and have been unable to find any examples like it help me with figuring it out.

If you could confirm my answer (i really think its wrong) or show me what i should be doing then that'd be great.
 
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Where did the 4 in 4/52 come from?
 
there are four aces in a deck of cards
 
But didnt the question ask for diamonds, not aces?

Three cards are dealt from a standard deck of 52 cards. What is the probability that all of them will be diamonds?
 
awwwwwwwwwwwwwwwwwww
 
ok thank you, I can do it now... sorry about that
 
on a different note, can you delete threads?
 
I think only moderators can delete threads.
 
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