Calculating the ratio between heat capacities of a gas

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SUMMARY

The discussion focuses on calculating the ratio of specific heats (gamma) for a gas, defined as gamma = Cp / Cv. Key formulas include Cp = Cv + R, where R is the gas constant, and Cv values of 3R/2 for monatomic gases and 5R/2 for diatomic gases. The user learns that for adiabatic processes, the relationship PV^gamma = K can be utilized to determine gamma. The conversation emphasizes the importance of correctly identifying the type of gas and the implications of assumptions made during calculations.

PREREQUISITES
  • Understanding of specific heat capacities (Cp and Cv)
  • Familiarity with the ideal gas law and gas constant (R)
  • Knowledge of adiabatic processes and their characteristics
  • Basic principles of thermodynamics, including the energy equipartition theorem
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  • Research the derivation of Cv and Cp for different types of gases
  • Learn about the energy equipartition theorem in detail
  • Explore the implications of adiabatic versus diabatic processes in thermodynamics
  • Study methods for determining the molecular composition of gases based on gamma values
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DoubleHelix
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Hi, my task is to calculate the ratio (gamma) between the specific heats of a gas (Cp and Cv). The only information I have is a table of data for the pressures and volumes of the gas at different temperatures. I don't know if its monatomic, diatomic etc. (it's a later task to determine this).

My attempt so far. I've been researching this for hours and I've discovered that the ratio I need to find is gamma = Cp / Cv. I've learned that Cp = Cv + R where R is the gas constant and that Cv = 3R/2 for a monatomic gas, 5R/2 for a diatomic gas and that Cp = 5R/2 for a monatomic gas, 7R/2 for a diatomic gas but have been unable to find where these numbers come from! I also found a useful formula that
gamma = 1 + (R/Cv) so I only really need to find either Cv or Cp using my data to solve this question.

Thanks for any help.
 
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What kind of transformation is the gas doing?

If it is diabatic, then you can find \gamma from PV^{\gamma}=K, and then compare that value with the theoretical values of \frac{C_p}{C_v} and find out what kind of molecule the gas is made of.

Here's an example for a monoatomic gas: It has 3 translational degrees of freedom, no rotation and no vibration, so N=3, and by the energy equipartition theorem you have a total energy of
U=n(3+0+0)\frac{1}{2}RT
where n is the mole number.

In order to calculate C_v you can prove that
C_v=\frac{1}{n}(\frac{dU}{dT})_{v=const}
and because
C_p=C_v+R you know the theoretical \gamma.
 
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After reading your reply I read through the question again and noticed that it mentions the the gas is undergoing adiabatic expansion in a later part of the question, I never read this far into the question before so I didn't realize. Would the relation you mentioned hold true for an adiabatic expansion? I'm going to do more research with this new found information!

Thanks a lot!
 
It holds for any adiabatic process,in other words, any process in which there is no heat exchange between the system and the surrounding universe.
 
Gunthi said:
What kind of transformation is the gas doing?

If it is diabatic, then you can find \gamma from PV^{\gamma}=K, and then compare that value with the theoretical values of \frac{C_p}{C_v} and find out what kind of molecule the gas is made of.

Here's an example for a monoatomic gas: It has 3 translational degrees of freedom, no rotation and no vibration, so N=3, and by the energy equipartition theorem you have a total energy of
U=n(3+0+0)\frac{1}{2}RT
where n is the mole number.

In order to calculate C_v you can prove that
C_v=\frac{1}{n}(\frac{dU}{dT})_{v=const}
and because
C_p=C_v+R you know the theoretical \gamma.

OK so I had a go at using the method you told me and, I did:
\frac{C_p}{C_v} = \frac{C_v + R}{C_v}
= \frac{\frac{1}{n}(\frac{dU}{dT}) + R}{\frac{1}{n}(\frac{dU}{dT})}

And assumed (for now) that it is a monatomic gas to calculate a set of U values which I plotted against the T values and drew a trendline through these points to get the gradient. Now, I (wrongly) canceled the top and bottom n to get

\frac{C_p}{C_v} = \frac{(\frac{dU}{dT}) + R}{(\frac{dU}{dT})}

and substituted the values into get 1.66 which relates to H or He. However, as I stated I wrongly canceled the ns I think, or am I allowed the cancel the ns? This means n must equal 1 BUT it's a later part of the question to calculate n which is why I'm panicing a little! Also I assumed monatomic gas, is there no way to do this for a general case because it's also a later part of the question to determine if its monatomic/diatomic etc. lol. I have all the answers but in the wrong order!
Thanks a lot anyway, you've been a great help. Do you have any other ideas?
 

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