Heat capacity for a real gas using the ideal gas (zero pressure) equation

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SUMMARY

The forum discussion centers on calculating the heat capacity of a real gas using the ideal gas equation at zero pressure. The participants debate the derivation of the equation \(C_p = C_p^0 - 2RT \int_0^P \frac{1}{P} \frac{\partial z}{\partial T} dP - RT^2 \int_0^P \frac{1}{P} \frac{\partial^2 z}{\partial T^2} dP\) and the confusion surrounding the transition from reduced properties to the specific heat capacity value of \(1.70 \, \text{cal/molK}\). The discussion highlights the importance of the generalized compressibility chart and the need for accurate differentiation techniques in thermodynamics.

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  • Study the derivation of the heat capacity equation \(C_p = C_p^0 - 2RT \int_0^P \frac{1}{P} \frac{\partial z}{\partial T} dP - RT^2 \int_0^P \frac{1}{P} \frac{\partial^2 z}{\partial T^2} dP\).
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  • #31
Chestermiller said:
If ##y(p_r,T_r)## is the ordinate on the plot, then a 2nd order accurate numerical approximation to the residual heat capacity is $$\frac{C_p^R}{R}=\frac{y(0.1,0.9)-y(0.1,0.7)}{0.9-0.7}$$
i'm confused, the ordinate is
1626241983176.png
with enthalpy, H explicitly stated. how have you arrived at this
1626242086267.png
? where has the critical temp, Tc term disappeared to?
I've also found this equation in perry's but nothing to convert to cp:
1626242262427.png
 
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  • #32
gmaverick2k said:
i'm confused, the ordinate is View attachment 285928with enthalpy, H explicitly stated. how have you arrived at this View attachment 285929? where has the critical temp, Tc term disappeared to?
I've also found this equation in perry's but nothing to convert to cp:
View attachment 285930
$$\frac{\partial \left(\frac{H^R}{RT_c}\right)}{\partial T_r}=\frac{\partial \left(\frac{H^R}{RT_c}\right)}{\partial (T/T_c)}=\frac{1}{R}\frac{\partial H^R}{\partial T}=\frac{C_p}{R}$$

Regarding Eqn. 4-168, you differentiate each term separately
 
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  • #33
Chestermiller said:
$$\frac{\partial \left(\frac{H^R}{RT_c}\right)}{\partial T_r}=\frac{\partial \left(\frac{H^R}{RT_c}\right)}{\partial (T/T_c)}=\frac{1}{R}\frac{\partial H^R}{\partial T}=\frac{C_p}{R}$$

Regarding Eqn. 4-168, you differentiate each term separately
ok, using plot digitizer for points on both graphs..
1626290592815.png

1626290599947.png


1626290606536.png

1626290614078.png

1626290637553.png

Yes, it looks like the author has overestimated the heat capacity by a factor of two assuming this is the correct methodology. I wish authors didn't skip on the working outs. i guess the fun is in the connecting of dots..
Thanks
 

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