Calculating the Temperature Change of Water After a Raindrop Strike

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To calculate the temperature change of the water after a raindrop strike, first determine the kinetic energy of the raindrop using the formula KE = 0.5 * m * v^2, which results in 800 J for a 1 g raindrop at 40 m/s. This energy is assumed to be fully transferred to the 100 g of water. Using the equation for heat transfer, set the heat gained by the water equal to the kinetic energy of the raindrop: 800 J = 100 g * C * ΔT, where C is the specific heat capacity of water (approximately 4.18 J/g°C). Solving for ΔT gives the change in temperature of the water. The final result indicates how much the water's temperature increases due to the impact of the raindrop.
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A raindrop (mass=1.00g) is traveling at a speed of 40m/s when it hits the surface of 100g of water contained in a drinking glass. What is the change in temperature of the water in the glass if we assume that i)all the kinetic energy of the raindrop is converted to energy that changes the water's temperature, and ii)the water in the glass and the raindrop were at the same original temperature?

I found the kinetic energy of the raindrop, but I don't know what to do after that. Please help. Thanks.
 
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You need the equation "heat lost by 1 g = heat gained by 100 g"
and the formula "heat gained or lost = m*C*ΔT"
 

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