Calculating the Velocity of a Proton using Magnetic Field and Electric Charge

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SUMMARY

The velocity of a proton can be calculated using the equation B = (μ₀ * q * v) / (4 * π * r²). In this discussion, the user rearranged the equation to solve for velocity (v), substituting the magnetic field strength (B) of 1.1 x 10^-3 T, the charge of the proton (q) as 1.6 x 10^-19 C, and the radius (r²) as 1.8 x 10^-5 m. This calculation resulted in a proton velocity of 1.2 x 10^8 m/s. Additionally, the user inquired about applying the right-hand rule to determine the proton's direction.

PREREQUISITES
  • Understanding of electromagnetic theory
  • Familiarity with the right-hand rule in physics
  • Knowledge of fundamental constants such as μ₀ (permeability of free space)
  • Basic algebra for rearranging equations
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  • Study the application of the right-hand rule in electromagnetic contexts
  • Explore the concept of magnetic fields and their effects on charged particles
  • Learn about the significance of the permeability of free space (μ₀) in calculations
  • Investigate advanced topics in particle physics related to proton behavior
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Students in physics, educators teaching electromagnetism, and anyone interested in the dynamics of charged particles in magnetic fields.

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Proton's Velocity

Homework Statement


MN4Ep.jpg


What is the speed of the proton?


Homework Equations


B=u0qv/(4pir^2)


The Attempt at a Solution



I rearranged the equation so that I solve for velocity, v. I determined that r^2 is 1.8*10^-5 m. I plugged in 1.1*10^-3 for B. The q for the proton is 1.6*10^-19.

Plugging all that and the constants in gave me a velocity of 1.2*10^8 m/s.
 
Last edited:
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Oh yeah, do you guys know the specific right hand rule for this situation? I need to use it to figure out the direction of this proton.
 

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