Calculating the Volume of a 6-Sided Box

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The discussion centers on calculating the volume of a box with six faces, where the top and bottom faces are square and the other faces are identical. Participants suggest that the shape resembles a pyramidal frustum and share the volume formula V=1/3(A1 + A2 + √(A1*A2))(h). One user calculates the volume using A1=100, A2=16, and h=6 cm, arriving at 220 cm³, while the expected answer is 312 cm³. The conversation emphasizes verifying the values used in the formula to ensure accuracy. The correct application of the formula is crucial for determining the volume accurately.
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Homework Statement



The diagram shows a box that has six faces .The top and bottom faces are square . THe other faces are all identical. What is the volume of the box ?

Homework Equations





The Attempt at a Solution

 

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What's your attempt so far? I.e. method and calculations? :smile:
 
Hint: It is Pyramidal Frustum. Correct me if I am wrong.
 
njama said:
Hint: It is Pyramidal Frustum. Correct me if I am wrong.

No that's what I was thinking too :wink: cheers njama on posting the link :smile:

OK, so thereddevils give that a go now! :smile:
 
Axiom17 said:
No that's what I was thinking too :wink: cheers njama on posting the link :smile:

OK, so thereddevils give that a go now! :smile:

ok so from the formula for volume of a pyramidal frustum is given by

V=1/3(A1 + A2 + root(A1)(A2))(h)

the height is root(18)

A1=100 , A2=16

i got V=220 cm^3

but the answer given is 312 cm^3.
 
According to the diagram h = 6 cm.
 
Yes the formula is:

V=\frac{1}{3}h \left( A_{1}+A_{2}+\sqrt{A_{1}\times A_{2}} \right)

Where A_{1} is the bottom area, A_{2} is the top area, and h is the height. Refer to your diagram for these values.

If you check that you're using all of the correct values :wink: , then you'll get the answer.

:smile:
 
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