- #1
nathan27th
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Hi if I had the ratio of 4:1 and the frequency of 10Khz how would I go about finding the time?
Calculating Time from 4:1 Mark-Space Ratio @ 10KHz
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Discussion Overview
The discussion revolves around calculating time based on a 4:1 mark-space ratio at a frequency of 10 kHz. Participants explore the relationship between frequency, duty cycle, and time intervals, addressing both theoretical and practical aspects of the problem.
Discussion Character
- Technical explanation
- Mathematical reasoning
- Debate/contested
Main Points Raised
- Some participants propose that the entire wave period at 10 kHz is 100 µs, with the active part being 80 µs based on a 4:1 ratio.
- One participant calculates the active time by dividing the ratio parts, suggesting that the active part (4) over the total parts (5) gives a duty cycle of 0.8, leading to 80 µs of active time.
- Another participant expresses uncertainty about the interpretation of the 4:1 ratio, indicating it could imply different percentages (20%, 25%, 75%, or 80%) depending on how it is understood.
- There is a suggestion that the term "mark-space ratio" is synonymous with duty cycle, which may clarify the discussion for some participants.
Areas of Agreement / Disagreement
Participants exhibit some agreement on the calculation of time based on the frequency and the 4:1 ratio, but there is disagreement regarding the interpretation of the ratio itself and its implications for the duty cycle.
Contextual Notes
The discussion highlights potential ambiguities in the definition of the mark-space ratio and its application in calculating time, as well as the assumptions made in the calculations presented.
Who May Find This Useful
This discussion may be useful for individuals interested in signal processing, electronics, or those needing clarification on duty cycles and frequency calculations.
- #2
berkeman
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Who which what?nathan27th said:
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Jeff Rosenbury
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Perhaps you could cut back on other activities? It's always hard to find time, but if something is important most people manage. 
Another term for the mark space ratio is duty cycle.
At 10kHz, the entire wave is 100µs and the active part (usually the high part) is 4/5th of that, so 80µs.
To get this I divided 1 cycle by 10,000 cycles per second and got 1/10,000 (100µs) of a second. Since the mark space ratio divides the cycle into parts, I divided the active parts of the ratio (4) by all the parts of the ratio (4+1=5) and got 0.8. I then multiplied 100µs times 0.8 and got 80µs.
I wasn't really clear what you are asking, but this might answer your question.
Another term for the mark space ratio is duty cycle.
At 10kHz, the entire wave is 100µs and the active part (usually the high part) is 4/5th of that, so 80µs.
To get this I divided 1 cycle by 10,000 cycles per second and got 1/10,000 (100µs) of a second. Since the mark space ratio divides the cycle into parts, I divided the active parts of the ratio (4) by all the parts of the ratio (4+1=5) and got 0.8. I then multiplied 100µs times 0.8 and got 80µs.
I wasn't really clear what you are asking, but this might answer your question.
- #4
Baluncore
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Frequency = 10 kHz. Therefore period, T = 1 / 10k = 100 usec.nathan27th said:
Ratio 4:1 could mean ( 4 marks + 1 space ) = 20%
That would give mark time = 4/5 * 100 usec = 80 usec and the space time = 20 usec.
The “ratio of 4:1” is a bit confusable. It might mean 20%, 25%, 75% or 80%.
A “ratio” suggests a simple division, not a relative proportion such as 4:1 = 4 / (4 + 1 ).
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