nathan27th
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Hi if I had the ratio of 4:1 and the frequency of 10Khz how would I go about finding the time?
Calculating Time from 4:1 Mark-Space Ratio @ 10KHz
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Jeff Rosenbury
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Perhaps you could cut back on other activities? It's always hard to find time, but if something is important most people manage. 
Another term for the mark space ratio is duty cycle.
At 10kHz, the entire wave is 100µs and the active part (usually the high part) is 4/5th of that, so 80µs.
To get this I divided 1 cycle by 10,000 cycles per second and got 1/10,000 (100µs) of a second. Since the mark space ratio divides the cycle into parts, I divided the active parts of the ratio (4) by all the parts of the ratio (4+1=5) and got 0.8. I then multiplied 100µs times 0.8 and got 80µs.
I wasn't really clear what you are asking, but this might answer your question.
Another term for the mark space ratio is duty cycle.
At 10kHz, the entire wave is 100µs and the active part (usually the high part) is 4/5th of that, so 80µs.
To get this I divided 1 cycle by 10,000 cycles per second and got 1/10,000 (100µs) of a second. Since the mark space ratio divides the cycle into parts, I divided the active parts of the ratio (4) by all the parts of the ratio (4+1=5) and got 0.8. I then multiplied 100µs times 0.8 and got 80µs.
I wasn't really clear what you are asking, but this might answer your question.
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Frequency = 10 kHz. Therefore period, T = 1 / 10k = 100 usec.nathan27th said:
Ratio 4:1 could mean ( 4 marks + 1 space ) = 20%
That would give mark time = 4/5 * 100 usec = 80 usec and the space time = 20 usec.
The “ratio of 4:1” is a bit confusable. It might mean 20%, 25%, 75% or 80%.
A “ratio” suggests a simple division, not a relative proportion such as 4:1 = 4 / (4 + 1 ).