Calculating Time of Flight for Artillery Shell

AI Thread Summary
To calculate the total time of flight for an artillery shell fired at an angle of 85.1 degrees with an initial speed of 1960 m/s, the vertical component of the velocity must be determined using trigonometric functions. The vertical velocity can be found by applying the sine function to the initial speed and angle, resulting in a vertical velocity of approximately 1959.6 m/s. The time of flight can then be calculated using the formula that incorporates gravity, where the total time is twice the time taken to reach the maximum height. Since no horizontal forces act on the shell, the problem simplifies to a vertical motion scenario. Understanding kinematic equations is essential for solving this type of projectile motion problem.
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I am completely lost on this one; An artillery shell is fired at an angle of 85.1 degrees above the horizontal ground with an initial speed of 1960 m/s. The acceleration of gravity is 9.8 m/s/s. Find the total time of flight. Can someone do it and explain how to do it?? Thanks so much!
 
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The trick to these questions is that no forces act on the shell horizontally so it is equivalent to a shell fired vertically with a certain velocity.
You find the vertical componnet of the velocity by drawing a 'force triangle' if the shell goes at 1960m/s at that angle draw a triangle with this as the hypotonuse and the angle given in the question.
 
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