Calculating Torque: Net Torque for 2 Forces Applied in a Plane

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To calculate the net torque from two forces acting on a rod, first resolve the forces into their components and apply the torque formula τ = rFsin(θ). The discussion highlights the importance of calculating the torques due to each force separately before summing them for the net torque. It clarifies that torque is positive for counterclockwise rotation and negative for clockwise rotation. A participant initially miscalculated the problem but was guided to correct their approach. Understanding these principles will help in solving similar torque problems effectively.
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Calculate the net torque about point for the two forces applied as in the figure below

The rod and both forces are in the plane of the page.

torque= ? Nm

http://session.masteringphysics.com/problemAsset/1026433/5/yg.10.42.jpg

is the answer -28 Nm?

i really need help I am not sure how to do problems with two forces
 
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cali_sk8er205 said:
Calculate the net torque about point for the two forces applied as in the figure below

The rod and both forces are in the plane of the page.

torque= ? Nm

http://session.masteringphysics.com/problemAsset/1026433/5/yg.10.42.jpg

is the answer -28 Nm?

i really need help I am not sure how to do problems with two forces

Remember:

\tau=rF_t=r_{\bot}F=rFsin\theta

So you have to resolve F2 into it's vertical and horizontal components for a start, then calculate the net torque and work from there.
 
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can you walk me through it?
ok how i think you do it is

12N*2m*sin30
-8N*5m
then add the two

sorry I am really not good at this
 
Please don't apologise, we all know what it's like :smile:

Also, I've corrected it now, but I made a mistake in my initial post, you should calculate the torques due to both forces and then the net torque (not force like I initially mentioned, sorry about that slip).

I also notice that I edited my equation for torque, but that it never changed the equation so I'll say it again.

\tau=rF_t=r_{\bot}F=rFsin\theta

Torque can be calculated as any of the following:

In other words the torque due to F_2 can be calculated using:

\tau_2=rFsin\theta

and for F_1

\tau_1=rF_t

Finally, torque is positive when counterclockwise and negative when clockwise.

That should sort you out :wink:

Try again and let us know how far you got ok?
 
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