Calculating Total Energy of Object

AI Thread Summary
To calculate the total energy of an object at its highest point with a horizontal velocity, both potential energy (PE) and kinetic energy (KE) must be considered. For a mass of 5 kg at a height of 3 m, the potential energy is calculated as 147.15 J using the formula PE = mgΔh. The kinetic energy, with a horizontal velocity of 2 m/s, is 10 J, calculated using KE = 0.5mv². The total energy sums to 157.15 J, which remains constant during the object's motion, assuming no air resistance. The calculations provided are correct, confirming that both forms of energy contribute to the total energy at that point.
Sixty3
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Homework Statement


If a question asks to calculate total energy of an object that does have a horizontal velocity (constant, air resistance ignored), and it is at it's highest point so it's vertical velocity is zero.

I need to know how you'd calculate the total energy of this object.

Let's take mass as 5kg. And a highest point of 3m. Horizontal velocity of 2m/s. (I just made them up).


Homework Equations


Potential energy = mgΔh
Kinetic energy = 0.5mv^2


The Attempt at a Solution


Pe= 5*9.81*3 = 147.15J
Ke= 5*2^2= 20/2 = 10J

10+147.15= 157.15J

I was just wondering if I am not leaving anything out, or if I'm even doing it correct! Thanks
 
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Hi Sixty3 :smile:

(try using the X2 tag just above the Reply box :wink:)
Sixty3 said:
Let's take mass as 5kg. And a highest point of 3m. Horizontal velocity of 2m/s. (I just made them up).

Pe= 5*9.81*3 = 147.15J
Ke= 5*2^2= 20/2 = 10J

10+147.15= 157.15J

I was just wondering if I am not leaving anything out, or if I'm even doing it correct! Thanks

Yes, that's fine …

at launch, and when on return to the ground, its KE is 157.15J.

(btw, we normally put a capital 'E' in KE and PE :wink:)
 
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