MHB Calculating Uncertainties of Measured quantities (Physics)

[Joystar77]

d1 = 2.53 cm +/- .05 cm

d2 = 1.753 m +/- .001 m

0 = 23.5 degrees +/- .5 degrees

v1 = 1.55 m/s +/- .15 m/s

Using the measured quantities above, calculate the following. Express the uncertainty calculated value.

a = 4 v1^2 / d2

a = 4 (1.55 m/s +/-.15 m/s)^2 / 1.753 m +/- .001 m

a = 6.8 m/s ^2 / 1.754 m

a = 13.6 m/s / 1.754 m

a = 7.753705815

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d3 = 4 (d1 + d2)d3 = 4 (2.53 cm +/- .05 cm) + (1.753 m +/- .001 m)d3 = 10.12 cm +/- .2 cm + 7.012 m +/- .004 md3 = 10.32 cm + 7.016 m

I tried to work this problem out, but I don't understand it and think it's not right. Someone please help me with this problem.

 

[topsquark]

d1 = 2.53 cm +/- .05 cm

d2 = 1.753 m +/- .001 m

0 = 23.5 degrees +/- .5 degrees

v1 = 1.55 m/s +/- .15 m/s

Using the measured quantities above, calculate the following. Express the uncertainty calculated value.

d3 = 4 (d1 + d2)

d3 = 4 (2.53 cm +/- .05 cm) + (1.753 m +/- .001 m)

d3 = 10.12 cm +/- .2 cm + 7.012 m +/- .004 m

d3 = 10.32 cm + 7.016 m

I tried to work this out, but I don't think it's right so someone please help me.

There is no single formula that you can use to get errors. Which you use depends on what kind of experiment you are doing and what data you have. One of the typical ones in use is this:

Given x, y and their respective errors [math]\Delta x,~\Delta y[/math] and the equation z = x + y you can calculate
[math]\frac{\Delta z}{z} = \sqrt{ \left ( \frac{\Delta x}{x} \right ) ^2 + \left ( \frac{\Delta y}{y} \right ) ^2}[/math]

You can use the same formula for z = xy or z = x/y as well. If you have more variables, such as z = x + y + w just add a term for w under the square root.

-Dan