Calculating Unknown Forces in a Vector Diagram

AI Thread Summary
To solve for the forces Fa and Fb in the given mechanics problem, the resultant force of 970 N along the x-axis must be analyzed using vector components. The angles provided (20 degrees for Fa and 51 degrees for Fb) indicate that one force acts above the x-axis and the other below, affecting their y-components. The law of sines and cosines are appropriate for this calculation, but care must be taken to ensure correct application, particularly in determining the correct triangle configuration. The y-component of the resultant vector is zero, which means the sum of the y-components of Fa and Fb must also equal zero. Clarifying the direction of the forces and correctly applying the trigonometric laws will lead to the correct values for Fa and Fb.
Xiomara

Homework Statement


Hi, I'm having trouble with my first mechanics assignment and I'd appreciate some help.
So, an object is being pulled using two ropes (Fa and Fb) with a resultant force of 970 N along the x axis. Angle from Fa to the axis is 20 degrees, angle from fb to the axis is 51 degrees. I need to calculate Fa and Fb.

Homework Equations


I think that I need to use either law of sines or cosines but am not sure.
c^2=a^2+b^2-2abcos(c)
sin(A)/a=sin(B)/b=sin(C)/c

The Attempt at a Solution


I made a vector diagram (triangle). I then tried to find F a and b by plugging all my knowns into the law of sines and solving. sin(C)/c=sin(51)/970=8.0118, but when I try to calculate the others based on this I get very small numbers, less than one. What am I doing wrong??
 
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One thing that the problem does not specifically state, is the direction (above or below) the x axis. So think about this. It is being pulled along the x axis. What does this tell you about the y-component of the resultant vector? Intuitively, one vector will be above the x-axis, and the other below the x-axis.
 
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