Calculating Velocities, dip and depth of a refractor

  • Thread starter Thread starter loya Blaise
  • Start date Start date
  • Tags Tags
    Depth Geophysics
AI Thread Summary
The discussion focuses on calculating seismic velocities, dip, and depth of a refractor using data from a 225m spread of 16 geophones. The formula for velocity is defined as v=(x2-x1)/(t2-t1), where x represents distances from the shot point and t represents arrival times of seismic waves. Participants express difficulty in proceeding with the calculations without access to the attachment, which contains crucial data. A suggestion is made to refer to a specific source for guidance on time-distance plots and refraction calculations. The conversation emphasizes the need for additional information to effectively solve the problem.
loya Blaise
Messages
1
Reaction score
0
https://scontent-vie1-1.xx.fbcdn.net/v/t34.0-12/14955857_1113106435476531_5016282393940245289_n.jpg?oh=c2e50935ccd57a0863d5f00c5b56653a&oe=5821DD35

Shot point A and B are located at a 225m spread of 16 geophones. Using the data in the attachment, Find
1. The Velocities, V1and V2
2. The Dip()
3. The depth of the refractor, h

My understanding of the Problem
v=(x2-x1)/(t2-t1),,where V is d velocity and x1, x2 are distances of any two recording stations from the shot point(source),, t1 and t2 are the times of arrival of the seismic wave at d same stations.

i have tried ploting tA against Xa, and tB against Xb all on the same graph. but don't just know what to do nest.please help me out
 
 
Is there some reason the attachment won't open? It would help to know what other data you were given. Until I can think up a simple plan to attack the problem, try this source. My other problem is that I've always had an assistant do my LaTex presentations and I'd still be typing my reply next Tuesday. I would like to see what else is on the attachment.

http://appliedgeophysics.berkeley.edu/seismic/seismic_23.pdf
7.2.3 Time – Distance Plots
Refraction calculations start on page 15.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top