Calculating Velocity and Time Dilation in Special Relativity

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
struggles
Messages
49
Reaction score
0

Homework Statement


  1. A spaceship travels from Earth to the vicinity of the star that is measured by astronomers on Earth to be six light-years away. The spaceship and its occupants have a total rest mass of 32 000 kg. Assume that the spaceship travels at constant velocity. The time taken as measured by clocks on the spaceship is 2.5 years.
    1. (i) Compute the velocity of the spaceship. [3 marks]
    2. (ii) How long does the trip take as measured by clocks in the Earth’s

      inertial rest frame? [3 marks]

Homework Equations



x' = γ(x-ut)
t' = γ(t - ux/c2) where the dash frame is the object rest frame, u is the relative speed between frames
γ = 1/√(1-u2/c2)
v' = v-u/1-u2v/c2

The Attempt at a Solution



So I'm a bit stuck my the first part of the question.
So far I have determined that x = 6ly, t' = 2.5yrs. I'm getting a bit puzzled as to what I'm looking to find. Is it u
or v or are they the same thing in this case? regardless I cannot think of a way in which i have enough variables that allows me to compute a value. Any help would be greatly appreciated!
 
on Phys.org
Sometimes you have to chip away at it. See if you can solve for x'. (Hint: You'll need a different version of your first equation.)

struggles said:
I'm getting a bit puzzled as to what I'm looking to find. Is it u
or v or are they the same thing in this case?
You are solving for u. v is irrelevant: there's only one velocity in this problem.
 
Ok so I'm not sure if this works or not but this is what I've got:
t = γt' and t = x/u.
Combining this gives x/t' = uγ and then expanding this all out and rearranging gives a value for u. Would this method work?
 
struggles said:
Ok so I'm not sure if this works or not but this is what I've got:
t = γt' and t = x/u.
Combining this gives x/t' = uγ and then expanding this all out and rearranging gives a value for u. Would this method work?
That will do it. Good! :thumbup:
 
Thank you for your help!