Calculating Velocity of a 10kg Bicycle Down a 150m Hill

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SUMMARY

The discussion focuses on calculating the velocity of a 10kg bicycle descending a 150m hill under the assumption of zero energy losses. The primary method suggested for this calculation is the principle of energy conservation, which states that potential energy at the top of the hill converts entirely into kinetic energy at the bottom. The relevant formula for this scenario is derived from the conservation of mechanical energy: v = sqrt(2gh), where g is the acceleration due to gravity (approximately 9.81 m/s²) and h is the height of the hill (150m).

PREREQUISITES
  • Understanding of basic physics concepts, specifically energy conservation.
  • Familiarity with the formula for kinetic energy (KE = 0.5 * m * v²).
  • Knowledge of gravitational acceleration (g = 9.81 m/s²).
  • Ability to manipulate algebraic equations to solve for velocity.
NEXT STEPS
  • Research the derivation of the conservation of mechanical energy formula.
  • Learn how to apply the kinetic energy formula in practical scenarios.
  • Explore the effects of friction and air resistance on velocity calculations.
  • Study real-world applications of energy conservation in cycling and other sports.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of energy conservation and its application to real-world scenarios, particularly in cycling dynamics.

tuttyfruitty
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Hi, i am confused with where to start with.


A cyclist is on a bicycle with a mass of 10kg rolls down a hill 150m high. with zero losses what is the velocity of the bike at the bottom of the hill?

could some one please send me in the right direction with formulas
 
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Zero losses -> use energy conservation?
 
tuttyfruitty said:
Hi, i am confused with where to start with.


A cyclist is on a bicycle with a mass of 10kg rolls down a hill 150m high. with zero losses what is the velocity of the bike at the bottom of the hill?

could some one please send me in the right direction with formulas

Welcome to the PF.

Please use mfb's hint to show some effort on your question.
 

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