Calculating Vertical Height from Spring Potential Energy

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A .3 kg mass resting on a compressed spring with a spring constant of 2000 N/m will rise to a height determined by the potential energy stored in the spring. The potential energy (PE) in the spring is calculated as 1.6 J, which translates to gravitational potential energy when the mass is released. By equating the gravitational potential energy to the spring potential energy, a height of .54 m is derived. The height should be measured from the top of the spring, confirming that this value is correct. Understanding the relationship between spring potential energy and gravitational potential energy is crucial for solving such problems.
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Homework Statement


A .3 kg mass rest on top of a spring that has been compressed by .04 m. Neglect any frictional effects, and consider the spring to be massless. Then, if the spring has a constant k equal to 2000 n/m, to what height will the mass rise when the system is released.

Homework Equations



PE(spring)= (1/2)kx^2

KE= 1/2mv^2

The Attempt at a Solution



I got the PE in the system to be 1.6 J. I am not sure how this would translate into a vertical height. Thanks in advance!
 
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shotgunbob said:
I got the PE in the system to be .48 J.
How did you arrive at this?

I am not sure how this would translate into a vertical height.
Consider gravitational PE.
 
Doc Al said:
How did you arrive at this?


Consider gravitational PE.

I messed up, used PE=1/2kmx^2 for some reason. I got 1.6 J.

And in Grav. PE, the H should be the same as the H I am looking for so PE(grav)=PE(Spring).
Or maybe I am missing something.
 
Ok I got .54 m when i put Pe(grave)=Pe(spring). Thats an answer choice! Is this correct?
 
It depends on what the height is being measured with respect to. The initial position on top of the spring? Or the compressed position?
 
I suppose its the top of the spring
 
shotgunbob said:
I suppose its the top of the spring
That's what I would say. :wink:
 
Thank you!
 
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