Calculating & Visualizing Motion: 2kg Circular Motion

AI Thread Summary
A 2kg mass is undergoing circular motion with a radius of 0.4m, completing 20 revolutions per minute. The calculations for angular velocity, linear velocity, centripetal acceleration, and kinetic energy have been provided, yielding values of 2pi/3 rad/s, approximately 0.8377 m/s, 1.754 m/s², and 0.701 J, respectively. The user is seeking assistance with visualizing the motion at 0.5 seconds, specifically in drawing the position, velocity, and acceleration vectors. Guidance suggests drawing a circle with the initial and subsequent positions marked, along with the position vector from the center to the mass. The discussion emphasizes that the velocity vector will be tangential, and the centripetal acceleration will point towards the center of the circle.
toljin123
Messages
1
Reaction score
0

Homework Statement


A body of mass 2kg performs circular motion about a point O. The radius of the circle is 0.4m and the mass completes 20 revolutions per minute.Calculate:

1) the angular veloicty.
2)the linear velocity.
3) the centripetal acceleration,and
4) the kinetic energy
5) Draw a diagram showing the position vector, the velocity vector and acceleration vector at time t=0.5s

Answers for 1-4

1) = 2pi/3
2)(0.4) * (2pi/3) = 0.8377
3)(2pi/3)^2(0.4) = 1.754
4)1/2(2)(0.8377)^2 = 0.701 I have completed 1-4, but i having some trouble doing number 5. Any help would be great :)
 
Last edited:
Physics news on Phys.org
toljin123 said:

Homework Statement


A body of mass 2kg performs circular motion about a point O. The radius of the circle is 0.4m and the mass completes 20 revolutions per minute.Calculate:

1) the angular veloicty.
2)the linear velocity.
3) the centripetal acceleration,and
4) the kinetic energy
5) Draw a diagram showing the position vector, the velocity vector and acceleration vector at time t=0.5s

Answers for 1-4

1) = 2pi/3
2)(0.4) * (2pi/3) = 0.8377
3)(2pi/3)^2(0.4) = 1.754
4)1/2(2)(0.8377)^2 = 0.701


I have completed 1-4, but i having some trouble doing number 5. Any help would be great :)

Hi Toljin, welcome to PF !

Draw a circle - is it ready? Place a dot on the circumference, indicating the initial position of the body (we assume it small with respect to the radius), and also its position 0.5 s later.

The position vector is just a vector drawn from the centre of the circle to the body.

What do you know about the velocity vector?
tangent to the circle
The angular velocity is constant, so you get only centripetal acceleration. What is its direction?

ehild
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top