Calculating Vo in an AC Circuit Using Superposition Theorem

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The discussion revolves around calculating the output voltage (Vo) in an AC circuit using the superposition theorem. A participant expresses confusion over the application of Kirchhoff's Voltage Law (KVL) and the given answer of 6.66L33.67 Volts. Clarifications are provided regarding the influence of a 6 amp current source on the circuit, emphasizing that it does not alter the voltage of a 12-volt source. The conversation highlights the simplification of the circuit by removing components that do not affect Vo, leading to two meshes for solving. The use of the superposition theorem is confirmed as a valid approach in this context.
Michael_0039
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This is the circuit:
01.PNG
I try with KVL:

1.PNG

New Doc 2019-09-24 23.36.18_1.jpg

New Doc 2019-09-24 23.36.18_2.jpg


But the given answer is 6.66L33.67 Volts. So, I'm confused, any suggestions ?
 
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May I ask a question ?
I assume that you wrote a zero on the left side of the first loop equation, but why ?
 
The 6 amp current source injects 6 amps into the node at the top of the 12 volt voltage source, and the 2 ohm resistor doesn't change that fact. Injecting 6 amps into a voltage source doesn't change the voltage of the 12 volt source. The net result of what I've said so far is that you can get rid of the current source and the resistor in series with it; those things have no effect on Vo. Now you have only two meshes to solve.
 
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alan123hk said:
May I ask a question ?
I assume that you wrote a zero on the left side of the first loop equation, but why ?
Because in this loop there is no Voltage source. The same on loop 3.
 
Thanks for your answers!

I try with Superposition theorem, I think this process is correct:

New Doc 2019-09-25 13.33.24_3.jpg

New Doc 2019-09-25 13.33.24_2.jpg
 

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