Calculating Vo in an AC Circuit Using Superposition Theorem

Click For Summary

Discussion Overview

The discussion revolves around calculating the output voltage (Vo) in an AC circuit using the superposition theorem. Participants are exploring the application of Kirchhoff's Voltage Law (KVL) and addressing confusion regarding the circuit analysis and the given answer.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about the calculated output voltage (Vo) compared to a given answer of 6.66L33.67 Volts.
  • Another participant questions the reasoning behind writing a zero on the left side of the first loop equation, seeking clarification on the assumptions made.
  • A different participant explains that the 6 amp current source does not affect the voltage of the 12 volt source, suggesting that the current source and the series resistor can be eliminated from consideration for calculating Vo.
  • There is a repeated question about the zero in the loop equation, indicating a need for further clarification on the absence of a voltage source in that loop.
  • One participant mentions attempting to use the superposition theorem, indicating an ongoing exploration of the problem.

Areas of Agreement / Disagreement

Participants are engaged in a debate with multiple viewpoints regarding the circuit analysis, and no consensus has been reached on the correct approach or solution.

Contextual Notes

There are unresolved assumptions regarding the circuit configuration and the application of the superposition theorem, as well as the implications of eliminating certain components from the analysis.

Michael_0039
Messages
59
Reaction score
7
This is the circuit:
01.PNG
I try with KVL:

1.PNG

New Doc 2019-09-24 23.36.18_1.jpg

New Doc 2019-09-24 23.36.18_2.jpg


But the given answer is 6.66L33.67 Volts. So, I'm confused, any suggestions ?
 
Physics news on Phys.org
May I ask a question ?
I assume that you wrote a zero on the left side of the first loop equation, but why ?
 
The 6 amp current source injects 6 amps into the node at the top of the 12 volt voltage source, and the 2 ohm resistor doesn't change that fact. Injecting 6 amps into a voltage source doesn't change the voltage of the 12 volt source. The net result of what I've said so far is that you can get rid of the current source and the resistor in series with it; those things have no effect on Vo. Now you have only two meshes to solve.
 
  • Like
Likes   Reactions: Michael_0039
alan123hk said:
May I ask a question ?
I assume that you wrote a zero on the left side of the first loop equation, but why ?
Because in this loop there is no Voltage source. The same on loop 3.
 
Thanks for your answers!

I try with Superposition theorem, I think this process is correct:

New Doc 2019-09-25 13.33.24_3.jpg

New Doc 2019-09-25 13.33.24_2.jpg
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K