Calculating Volume of Cylinder w/ Fixed Dimensions on A4 Paper

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Homework Help Overview

The discussion revolves around calculating the volume of a cylinder formed from an A4 piece of paper with fixed dimensions of 30 cm by 21 cm. Participants explore the relationship between the cylinder's height and radius, and how these dimensions relate to the paper's constraints.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the radius and height of the cylinder, questioning how these dimensions can be derived from the fixed dimensions of the paper. Some explore different configurations for the cylinder's orientation relative to the paper, leading to varying volume calculations.

Discussion Status

There are multiple interpretations of how to configure the cylinder using the paper's dimensions. Some participants have provided calculations for volume based on different assumptions about the cylinder's height and radius, indicating a productive exploration of the problem without reaching a consensus.

Contextual Notes

Participants note that the volume of the cylinder is considered fixed under the outlined constraints, but they also explore alternative configurations that could yield different results. The discussion includes warnings about thinking outside the box regarding the cylinder's orientation.

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Homework Statement


Explain why, using this outline for creating the cylinder, the volume of the cylinder is fixed for an A4 piece of paper (30x21)
calc.jpg


Homework Equations


h=30-4R

I really don't know how to approach this question, i know it has something to do with the radius and the height of the cylinder. but i don't know how to prove it.
 
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The paper has certain dimensions, height = 21, width = 30.

A cylinder has a certain h, with circles of radius r at the base. Thus, if the radius of the circles are r, the width of the paper (30) must equal:

4*r + h = 30

(4 radii from two circles plus the height of the cylinder = width of the paper)

However the height of the paper must be equal to the circumference of one of the circles (2*pi*r) in order to form a cylinder:

2*pi*r = 21

thus r = (21/2*pi) or approximately 3.34 (cm)

giving us the value for h = 30 - 4*(21/2*pi). or approximately 16.63 (cm)

Making a cylinder with bases of diameter 6.68 cm and a height of 16.63 cm. and a volume of 2*pi*r^2*h = 2*3.14159*3.34^2*16.63

= 1165.64 cm^3

Which is the answer to the problem.

=== Warning, thinking outside the box:

However one can argue that one could put the height of the cylinder along the height of the paper, in which case:

4*r + 2*pi*r = 30 and (edit: that is, 4 radii of two circles plus the circumference of the cylinder's base = width of the paper)
h = 21

Which gives us as solutions:

r = 30/(4+2*pi) = approximately 2.92 cm
h = 21 cm

And a volume of 2*pi*r^2*h = 1125.03 cm^3

So theoretically there are two solutions to the problem. (but in any case the Volume of the cylinder is FIXED, that is a certain value).

JJ +
 
Last edited:
Bonus Question

Bonus Question !

Here is a bonus question that I thought of while looking at your question. It actually has an interesting answer:

http://ibphysics.org/images/cylinder-problem.jpg
 
Last edited by a moderator:
The maximum volume is:


607.3 cm^3
 

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