Calculating Volume of Object with Annular Slicing Method

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The discussion centers on calculating the volume of a hemisphere with a central hole using the annular slicing method. The initial calculation using horizontal slicing yielded a volume of (2/3)π(R² - a²)^(3/2). The user expresses confusion about how to apply the annular slicing method to subtract the volume of the hole from the hemisphere. Some participants suggest that the methods may not differ significantly and that using slicing on the hole could complicate the process. Clarification is sought on the specifics of applying annular slicing to this problem.
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Homework Statement
The question asks; An object is made of a hemisphere of radius 'R' with a hole of radius 'a' drilled through its center of symmetry, as shown in the figure. Use annular slicing to find the volume of the object.

Mm2cs.jpg
The attempt at a solution
I have managed to calculate the volume using the horizontal slicing method to be;

\frac{2}{3} π(R^{2}-a^{2})^{\frac{3}{2}}

Using;

V = \int_{body} dv(y) where dv(y) = π(R^{2}-y^{2}-a^{2})dy where y is height.

I can get the volume of the whole sphere using the annular slicing method but am unsure about how to subtract the volume of the hole from this and cannot find any information on how it is done using this method. Any help would be greatly appreciated!
 
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I don't see any difference between "annular slicing" and "horizontal slicing". I think you have already done the problem correctly. You could use slicing on the hole to figure out what to remove from the hemisphere, but I don't think that makes it any easier or different.
 
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Thanks for the quick reply. The lecture notes I have been given make it seem as there is a difference between the two.

Here is an earlier question;
A3g6k.jpg
 
For the annular slicing, isn't it just the annular integral for the hemisphere, but integrating from a non-zero smallest radius (namely...)?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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