Calculating Water Formation in Eudiometery: Oxygen and Hydrogen Reaction

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When 1 liter of oxygen (O2) and 1 liter of hydrogen (H2) are combined in a 2-liter vessel and ignited, they react to form water (H2O) in a 2:1 ratio of hydrogen to oxygen. This means that all of the hydrogen will react with half of the oxygen, resulting in the formation of 0.5 liters of water vapor. The remaining component in the vessel will be 0.5 liters of unreacted oxygen. The mass of the water formed is approximately 9 grams, calculated from the molecular weight of water. If the vessel is heated, the pressure inside will increase, but the exact pressure in mm of Hg will depend on the final temperature and volume conditions.
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1 litre of oxygen and 1 litre of hydrogen are taken in a vessel of 2 litre capacity at normal temperature pressure .The gases are made to combine by applying electric spark . Assume that water is formed quantitively .How many grams of water are formed? What is the other component present in the vessel and in what weight ? If the vessel is now heated ,what will be the pressure inside the vessel in mm of Hg ? :smile:
 
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Water is H2O so each water molecule requires one oxygen and two hydrogen atoms. How many oxygen atoms are there is a liter of oxygen (I assume at standard temperature and pressure- remember that molecular oxygen is O2-two atoms to each molecule- same for hydrogen, H2)? How many hydrogen atoms are there in a liter of hydrogen?

Matching up hydrogen and oxygen atoms in a 2 to 1 ratio (Again, water is H2O), are there enough hydrogen atoms to match all the oxygen atoms, are there enough oxygen atoms to match all the hydrogen atoms? If not, which will be left over? How many molecules of water can you make? What is the mass of that much water?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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