Calculating Wavelength and Energy of Excited Hydrogen Atom | Help Guide

fdizzy
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help please, for question: a hydrogen atom, initially in ground state, absorbs a photon, and is excited to its second excited state. What were the wavelength and the energy of the photon by the atom. Did i do it right.

1/λ = (1.097*10^7)(1/n1^2 - 1/n2^2)

1/λ = (1.097*10^7)(1/1^2 - 1/4^2)

λ = 9.72*10^-8 m


Energy = hc/λ

= (6.626*10^-34*3*10^8)/(9.72*10^-8)

= 2.045*10^-18 J
 
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You appear to be using 4 as the value of n for the second excited state. Why is that?
 
oh it should be 2 right ?
 
n = 1 is the ground state, which is not an excited state. So the first excited state would be...
 
so would it be 2
 
i think my n=1 would be 1 its grund state, excited state 2, would be n=3 ?
 
That's how I see it. :smile:
 
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