Calculating Wavelength and Expressions for Standing Waves | Homework Solution

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A standing wave on a 1.5m string with a frequency of 25Hz has a calculated wavelength of 1m. The maximum amplitude of the wave is 5cm, leading to expressions for the waves traveling in opposite directions. The wave traveling to the right is represented as y = 0.025cos(157t - 6.28x), while the reflected wave traveling to the left is y = 0.025cos(157t + 6.28x). The calculations for angular frequency and wave number are confirmed as correct. The solution effectively demonstrates the principles of standing waves and their mathematical representation.
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Homework Statement



A standing wave has been created on a string of length 1.5m. The frequency of the wave is 25Hz. The ends of the string are nodal points and there are 3 antinodes.
A)What is the wavelength of the standing wave?
B)If the maximum amplitude of the wave is 5cm, write complete expressions, including values for k and w, for the generated wave traveling to the right and the reflected wave traveling left. Take right as the +xˆ direction. (Hint: Remember the standing wave is the sum of two waves of equal amplitudes traveling in opposite directions.)

Homework Equations



omega=2pi*f
k=(2pi)/f

The Attempt at a Solution



A) L=(3*lambda)/2
so the wavelength = 1m

B) A=2.5cm = .025m
omega=2pi*f = 2pi(25) = 157 rad/s
k=(2pi)/h = 2pi/1 = 6.28m^-1

So in the right direction: y = 0.025cos(157t - 6.28x)
and the wave to the left is y = 0.025cos(157t + 6.28x)

Are these correct?
 
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It looks all right, good job.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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