Calculating Work on a Sliding Block: Mass, Speed, and Kinematics

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To calculate the work needed to bring a 3 kg block moving at 6 m/s to rest, the change in kinetic energy must be determined. The initial kinetic energy can be calculated using the formula KE = 1/2 mv^2, resulting in 54 J. Since the work done on the block equals the change in kinetic energy, 54 J of work is required to stop the block. The discussion emphasizes the importance of remembering the kinetic energy formula and its relation to work. Understanding these concepts is crucial for solving similar physics problems effectively.
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Homework Statement


A block of mass 3 kg, which has an initial
speed of 6 m/s at time t = 0, slides on a
horizontal surface.
Find the magnitude of the work that must
be done on the block to bring it to rest.
Answer in units of J.


Homework Equations


F=MA
W=FD
Kinematics
Vf=Vi=AT
ΔX=ViT=1/2AT2
2AΔX=Vf2-Vi2

The Attempt at a Solution


basically I need A and ΔX(D)... and I can't remember what to do. after that, it's a simple matter of plugging in numbers
 
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Hint: The change in kinetic energy is the same as the work done on the block.
 
yeah, ha, totally forgot about the other formula xD
 
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