Calculating Work: Pushing a Block Up a Frictionless Incline

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To calculate the work required to push a 25-kg block up a 2m frictionless incline at a constant speed, the relevant equations are W=F(delta X) and W=(F cos theta)(delta X). The normal force is calculated as n=mg, resulting in 245 N for the block's weight. It's crucial to consider the incline's angle when determining the force component acting along the ramp. The distance moved is indeed 2m, but the force must account for the gravitational component acting down the incline. Understanding these components is essential for accurately calculating the work done.
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Homework Statement


How much work is required to push a 25-kg block up 2m up a frictionless 30 degree incline at a constant speed?


Homework Equations


W=F(delta X) ; W=(F cos theta)(delta X)


The Attempt at a Solution


I did n=mg -- n=(25)(9.8)=245 & that is the correct answer..but I don't understand how.
 
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Well, by coincidence you didn't factor in the angle and still go the right answer.

Start off by having a coordinate plane that is parallel to the incline of the ramp. Figure out what component of the total weight (mg) you are pushing up the ramp and by what distance.
 
I don't think I understand what you mean. The distance is 2m and wouldn't the total weight simply be the weight of the block?
 

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