Calculating Work: Pushing a Block Up a Frictionless Incline

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SUMMARY

The discussion focuses on calculating the work required to push a 25-kg block up a 2-meter frictionless incline at a 30-degree angle. The relevant formula for work is W = F * (delta X), where F is the force component acting along the incline. The correct approach involves determining the gravitational force component acting parallel to the incline, which is calculated using W = (F cos θ)(delta X). The participant initially calculated the normal force but did not account for the incline angle, leading to confusion.

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Homework Statement


How much work is required to push a 25-kg block up 2m up a frictionless 30 degree incline at a constant speed?


Homework Equations


W=F(delta X) ; W=(F cos theta)(delta X)


The Attempt at a Solution


I did n=mg -- n=(25)(9.8)=245 & that is the correct answer..but I don't understand how.
 
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Well, by coincidence you didn't factor in the angle and still go the right answer.

Start off by having a coordinate plane that is parallel to the incline of the ramp. Figure out what component of the total weight (mg) you are pushing up the ramp and by what distance.
 
I don't think I understand what you mean. The distance is 2m and wouldn't the total weight simply be the weight of the block?
 

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