Calculating work with variable force

AI Thread Summary
The discussion focuses on understanding the calculation of work done by variable forces, specifically in the context of a physics problem involving a rock on a string. The user is confused about the assumption that the net force in the vertical direction is constant at mg, despite the presence of tension throughout the rock's path. It is clarified that tension, being perpendicular to the motion, does not perform work on the rock, meaning only gravity contributes to the work done. The key takeaway is that the work is calculated using the gravitational force, which remains constant, while the tension does not affect the work calculation. This highlights the importance of recognizing the role of different forces in work calculations.
forester404
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Homework Statement


Hi.
I am trying to learn some physics with MIT free resources (just out of personal interest),
and this is where i got stuck:
on section 14-13, in
http://ocw.mit.edu/courses/physics/8-01-physics-i-fall-2003/lecture-notes/binder13.pdf"
I am a little puzzled on how the work is calculated in the given solution - mgh,
where h is delta y between the 2 points. if i got it right, this calculation assumes
that the net force on y direction is mg and is constant throughout the path, but it seems
to me like the tension in the string is larger than 0 in every point along the path
except the very top of the circle (where it's 0 by porblem definition), and
always has some y component, so i don't understand how the net force in y direction
is a constant mg. what am i missing here ?

Homework Equations



W = integral from a to b (Fydy)

(sorry but i couldn't handle the LaTex renderer here...)

The Attempt at a Solution

 
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The tension in the string is always perpendicular to the motion, thus it does no work on the rock. Only gravity does work on the rock.
 
Thanks for the quick reply !
 
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