Calculation of capacitance of conductors

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SUMMARY

The discussion focuses on calculating the capacitance of conductors in a 2D space, emphasizing the need for accurate methods to determine capacitance between multiple conductors. The capacitance can be calculated using the formula C = εrε0 (A/d), where A is the area of overlap, d is the separation distance, εr is the relative permittivity, and ε0 is the permittivity of free space (8.854x10-12 F/m). The conversation highlights the limitations of this formula when the separation distance d is large compared to the dimensions of the conductors, leading to inaccuracies in results. Techniques such as segmenting conductors and applying Gauss's theorem were discussed but yielded unsatisfactory accuracy.

PREREQUISITES
  • Understanding of capacitance and its calculation methods
  • Familiarity with the formula C = εrε0 (A/d)
  • Knowledge of dielectric properties and their impact on capacitance
  • Basic principles of electric fields and Gauss's theorem
NEXT STEPS
  • Research advanced methods for calculating capacitance in non-uniform fields
  • Explore numerical simulation tools for capacitance analysis, such as COMSOL Multiphysics
  • Learn about finite element analysis (FEA) techniques for complex conductor geometries
  • Investigate the effects of fringing fields on capacitance measurements
USEFUL FOR

Electrical engineers, physicists, and researchers involved in capacitor design, antenna analysis, and electromagnetic field studies will benefit from this discussion.

Ravaner
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Hello,

I would like to get a method for calculation of capacitance of conductors. Let say, I have several conductors in space (2D). I know voltage everywhere between and on conductors, and I need to know the value of capacitance between 2 conductors among several. I'm looking for a general method in order to program an algorithm.
 
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The capacitance is determined by the dimensions of the conductors and the properties of the dielectrics between and around them.

Here is Wikipedias description:

The capacitance can be calculated if the geometry of the conductors and the dielectric properties of the insulator between the conductors are known. For example, the capacitance of a parallel-plate capacitor constructed of two parallel plates both of area A separated by a distance d is approximately equal to the following:

C = \epsilon_{r}\epsilon_{0} \frac{A}{d} (in SI units)

where

C is the capacitance in farads, F
A is the area of overlap of the two plates measured in square metres
εr is the relative static permittivity (sometimes called the dielectric constant) of the material between the plates, (vacuum =1)
ε0 is the permittivity of free space where ε0 = 8.854x10-12 F/m
d is the separation between the plates, measured in metres

The equation is a good approximation if d is small compared to the other dimensions of the plates so the field in the capacitor over most of its area is uniform, and the so-called fringing field around the periphery provides a small contribution


End quote.
A technique that is used to analyse radio antennas is to take small segments of each part of the antenna and calculate the effect of all other parts on that part, and vice versa.

So, if you knew the diameter of a wire, you could take a small section of it and work out the area facing each other section of other conductors and estimate the capacitance.
Wire segments along the same wire could have their capacitances added in parallel.
 


Thanks for reply. I've programmed this formula, resultats lack of accuracy bur anyway it's better that nothing. I've also tried using Gass theorem with calculation of flux for electrical field, results are not better !
 


Yes, even the Wikipedia article I quoted said this:

The equation is a good approximation if d is small compared to the other dimensions of the plates so the field in the capacitor over most of its area is uniform, and the so-called fringing field around the periphery provides a small contribution.

Meaning that it wasn't a good approximation if d, the separation between the plates, measured in metres, was large. And not if the so-called fringing field around the periphery provides a large contribution.

So, these problems might be contributing to the inaccuracy.
 

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