Calculation of Curie Constant for Iron in Metallic Form

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SUMMARY

The calculation of the Curie constant for iron in metallic form involves using the formula C = [(m^2)(mu)N]/[3K]. Given that the Curie temperature of iron is 1043 Kelvin and the magnetic moment per iron atom is 2 Bohr magnetons, the derived Curie constant is 0.89. However, the expected value from the textbook is 0.66, suggesting a potential oversight in the number of atoms per unit volume in the body-centered cubic structure of iron. The calculation confirms the need to verify atomic packing factors in such computations.

PREREQUISITES
  • Understanding of Curie temperature and its significance in magnetism
  • Familiarity with the concept of Bohr magneton and its application
  • Knowledge of body-centered cubic (BCC) crystal structures
  • Basic grasp of thermodynamic principles, particularly Boltzmann's constant
NEXT STEPS
  • Research the atomic packing factor for body-centered cubic structures
  • Learn about the implications of Curie temperature in ferromagnetic materials
  • Explore the relationship between magnetic moment and material properties in solid-state physics
  • Investigate the calculation methods for Curie constants in various materials
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Students and professionals in physics, particularly those focusing on magnetism and material science, as well as anyone involved in the study of ferromagnetic materials and their properties.

Amith2006
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Homework Statement



As none are responding to my query posted in Introductory Physics section, I am posting it here. Someone please guide me!
1)The curie temperature of iron is 1043 Kelvin. Assume that iron atoms, when in metallic form have moments of 2 Bohr magneton per atom. Iron is body centered cube with lattice parameter a = 0.286 nm. Calculate the curie constant.


Homework Equations


C = [(m^2)(mu)N]/[3K]



The Attempt at a Solution



I solved it in the following way:
Let m be the magnetic moment of an iron atom, N be the number of atoms per unit volume, K be the Boltzmann constant, mu be the permeability of free space and C be the Curie constant.
m = 2[m(B)] {where m(B) is Bohr magneton}
= 18.54 x 10^(-24) A-m^2
N = n/(a^3) {where n is number of atoms in 1 cubic lattice of iron}
= 2/[(0.286 x 10^(-9))^3]
= 8.5 x 10^28 atoms per unit volume
C = [(m^2)(mu)N]/[3K]
C = 0.89
But the answer given in my book is 0.66.
 
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I suspect the difference is related to the phrase "body centered cube". Are you sure there are 2 atoms per lattice cube? I'd check around under subjects like "atomic packing factor" to make sure.
 
On second thought the 2 seems ok. Hmm. I'm no expert in this field.
 
What on Earth is preventing you all from answering?
 

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