Magnetic moment calculation from curie constant (thought this was easy)

[mloving86]

Homework Statement

Need to calculate magnetic moment of FeRh from the curie constant which was obtained from a linear fit of inverse susceptibility data.

CGS units!

C = 68 (cm³K)/mole
N = Avogadro constant 6.022E23 atoms/mole
K = Boltzmann constant 1.38E-16 erg/K
uB = Bohr magnetons 9.274E-21 erg/G
ueff = unknown effective magnetic moment

want the solution in terms of bohr magnetons.

Relevant conversion factors:
erg = 4pi cm³Oe²
1 G = 4pi Oe

Homework Equations

u_eff=((3KC)/N)^1/2; which simplifies to u_eff= 2.84C^(1/2)

The Attempt at a Solution

($$\frac{3 * 1.38E-16 erg/K * 68 cm³K/mole}{6.022E23atom/mole}$$)^1/2

= ~24uB.

I expect my solution to be closer to 3.2. Does anyone know if there is something typically done after these sorts of calculations that I need to do?

 

[Sajad Ahmad Mir]

X=C/(T-T_c)
C= (T-T_c)X
C=(T-T_c)/(1/X)
C=(T-T_c)/X^-1
C= dT/dX^-1
In X^-1 vs T plot fit linear part of plot. Select two points and there by get two values for temperature and two for inverse susceptibility (X^-1) then substitute in the above equation to get Curie constant (C). Otherwise find the slope of fitted linear part of the plot and then take reciprocal of the slope that will be curie constant as ber the above equation.
After knowing Curie constat (C), the effective magnetic moment can be calculated as U_eff = 2.34 sqrt (C)