Magnetic moment calculation from curie constant (thought this was easy)

In summary, the problem at hand is to calculate the magnetic moment of FeRh from the Curie constant which was obtained from a linear fit of inverse susceptibility data. The solution is to use the equation u[SUB]eff=((3KC)/N)1/2, which simplifies to u[SUB]eff= 2.84C^(1/2), where C is the Curie constant in CGS units. To obtain C, a linear fit must be done on the plot of inverse susceptibility (X-1) vs temperature, and the slope of the linear part can be used to calculate C. Then, the effective magnetic moment can be calculated using the equation Ueff = 2.34 sqrt (C), and
  • #1
mloving86
1
0

Homework Statement



Need to calculate magnetic moment of FeRh from the curie constant which was obtained from a linear fit of inverse susceptibility data.

CGS units!

C = 68 (cm3K)/mole
N = Avogadro constant 6.022E23 atoms/mole
K = Boltzmann constant 1.38E-16 erg/K
uB = Bohr magnetons 9.274E-21 erg/G
ueff = unknown effective magnetic moment

want the solution in terms of bohr magnetons.

Relevant conversion factors:
erg = 4pi cm3Oe2
1 G = 4pi Oe

Homework Equations



ueff=((3KC)/N)1/2; which simplifies to ueff= 2.84C^(1/2)

The Attempt at a Solution


([tex]\frac{3 * 1.38E-16 erg/K * 68 cm3K/mole}{6.022E23atom/mole}[/tex])1/2

= ~24uB.

I expect my solution to be closer to 3.2. Does anyone know if there is something typically done after these sorts of calculations that I need to do?
 
Last edited:
Physics news on Phys.org
  • #2
X=C/(T-Tc)
C= (T-Tc)X
C=(T-Tc)/(1/X)
C=(T-Tc)/X-1
C= dT/dX-1
In X-1 vs T plot fit linear part of plot. Select two points and there by get two values for temperature and two for inverse susceptibility (X-1) then substitute in the above equation to get Curie constant (C). Otherwise find the slope of fitted linear part of the plot and then take reciprocal of the slope that will be curie constant as ber the above equation.
After knowing Curie constat (C), the effective magnetic moment can be calculated as Ueff = 2.34 sqrt (C)
 

What is a magnetic moment?

A magnetic moment is a measure of the strength and orientation of a magnetic field generated by a particle or object. It is a vector quantity, meaning it has both magnitude and direction.

What is the Curie constant?

The Curie constant, named after physicist Pierre Curie, is a material-specific constant that relates the magnetic moment to the temperature of a paramagnetic material. It is often denoted by the symbol C and has units of joules per tesla.

How is magnetic moment calculated from the Curie constant?

The magnetic moment can be calculated from the Curie constant using the equation μ = C/T, where μ is the magnetic moment and T is the temperature in kelvin. This equation assumes that the material follows the Curie law, which states that the magnetic susceptibility of a paramagnetic material is inversely proportional to its temperature.

What is the significance of calculating magnetic moment from the Curie constant?

Calculating the magnetic moment from the Curie constant allows scientists to understand and predict the behavior of paramagnetic materials at different temperatures. It can also provide insight into the magnetic properties of a material, such as its susceptibility and how it responds to an external magnetic field.

Are there any limitations to using the Curie constant for magnetic moment calculations?

Yes, there are limitations to using the Curie constant for magnetic moment calculations. This method assumes that the material follows the Curie law, which is not always the case. Additionally, the Curie constant may vary with temperature and may not accurately represent the magnetic behavior of a material as the temperature changes.

Similar threads

  • Advanced Physics Homework Help
Replies
2
Views
1K
  • Advanced Physics Homework Help
Replies
2
Views
2K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
25
Views
279
  • Advanced Physics Homework Help
Replies
3
Views
19K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Advanced Physics Homework Help
Replies
4
Views
5K
  • Introductory Physics Homework Help
Replies
2
Views
6K
  • Biology and Chemistry Homework Help
Replies
2
Views
6K
Replies
11
Views
4K
Back
Top