yeyintkoko
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Anyone can explain me this example?
I substitute value for
e = 1.602*10-19;
m0 = 9.1*10-31;
pi = 3.14;
and calculated value for μav in matlab.
I received 1.7104*10-19. But in exam this value is 0.68*10-25.
What is i wrong?
please help me.
Thank you.
I substitute value for
e = 1.602*10-19;
m0 = 9.1*10-31;
pi = 3.14;
and calculated value for μav in matlab.
I received 1.7104*10-19. But in exam this value is 0.68*10-25.
What is i wrong?
please help me.
Thank you.