Calculus: Coordinate Changes, Jacobian, Double Integrals?

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SUMMARY

The discussion centers on the transformation T(u,v) = (u² - v², 2uv) and its application to calculate the double integral ∬√(x²+y²) dxdy over the domain D, defined by the triangle { (u,v) | 0 ≤ v ≤ u ≤ 3 }. The Jacobian for the transformation is established as dxdy = (4u² + 4v²)dudv. Participants emphasize the importance of visualizing the uv region to determine the correct bounds for integration, ultimately leading to a solved integral result of 4536/5 or 907.2.

PREREQUISITES
  • Understanding of double integrals in calculus
  • Familiarity with Jacobian transformations
  • Knowledge of coordinate systems and transformations
  • Ability to graphically represent regions in the uv-plane
NEXT STEPS
  • Study the properties of Jacobians in multivariable calculus
  • Learn how to visualize and sketch regions for double integrals
  • Explore advanced applications of coordinate transformations in calculus
  • Investigate the implications of integral results in geometric contexts
USEFUL FOR

Students and educators in calculus, particularly those focusing on multivariable calculus, coordinate transformations, and double integrals. This discussion is beneficial for anyone seeking to enhance their understanding of Jacobians and integration techniques.

PinkPocky
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Calculus: Coordinate Changes, Jacobian, Double Integrals??

Homework Statement



Show that T(u,v) = (u2 - v2, 2uv)
maps to the triangle = { (u,v) | 0 ≤ v ≤ u ≤ 3 } to the domain D,
bounded by x=0, y=0, and y2 = 324 - 36x.

Use T to calculate ∬sqrt(x2+y2) dxdy on the region D.


Homework Equations



The Attempt at a Solution



I know that dxdy = the Jacobian = (4u2+4v2)dudv.

I'm have a really hard time finding a way to figure what the bounds of the integral are, in terms of u and v.
 
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PinkPocky said:

Homework Statement



Show that T(u,v) = (u2 - v2, 2uv)
maps to the triangle = { (u,v) | 0 ≤ v ≤ u ≤ 3 } to the domain D,
bounded by x=0, y=0, and y2 = 324 - 36x.

Use T to calculate ∬sqrt(x2+y2) dxdy on the region D.


Homework Equations



The Attempt at a Solution



I know that dxdy = the Jacobian = (4u2+4v2)dudv.

I'm have a really hard time finding a way to figure what the bounds of the integral are, in terms of u and v.

Try drawing a picture of the uv region. You have 0 ≤ v ≤ u ≤ 3 given. Both u and v are between 0 and 3 so draw that square for a start. Now shade what part of that square also has v ≤ u. Then put your uv limits as that picture requires, like any other area problem.
 


Great, thanks! I should have realized it before... but thank you, a really great explanation made it clear for me to help myself. :)

By the way, the final answer to the problem I solved for was ridiculous but correct. The solved integral is equal to 4536/5, or 907.2 :(... haha.
 

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